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AnnZ [28]
2 years ago
7

Can someone please explain how I am supposed to do this I do not understand at all whatsoever.

Mathematics
1 answer:
Leni [432]2 years ago
7 0

Answer:

B. (6,-3)

Step-by-step explanation:

3x - 5y ≥ 10

(1,4) IS NOT a solution to the equation

3(1) - 5(4) ≥ 10

3 - 20 ≥ 10

- 17 ≥ 10

3x - 5y ≥ 10

(6,-3) IS a solution to the equation

3(6) - 5(-3) ≥ 10

18 + 15 ≥ 10

33 ≥ 10

3x - 5y ≥ 10

(-5,-2) IS NOT a solution

3(-5) - 5(-2) ≥ 10

-15 + 10 ≥ 10

-5 ≥ 10

3x - 5y ≥ 10

(2,0) IS NOT solution

3x - 5y ≥ 10

3(2) - 5(0) ≥ 10

6 - 0 ≥ 10

6 ≥ 10

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Determine the slop of the line passing through (-3,7) and (9,-2)
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What is the LCD for the given equation?
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5 0
3 years ago
find the value of a and b for which the system of equations has infinitely many solutions : 2x + 3y = 7 ; (a-b)x + (a+b)y = 3a +
hodyreva [135]

Answer:

a= 5    and   b=1

Step-by-step explanation:

To solve, we will follow the steps below:

2x + 3y = 7

(a-b)x + (a+b)y = 3a + b - 2​

We should note that since it has infinitely many solutions then,

\frac{a_{1} }{a_{2} }   =  \frac{b_{1} }{b_{2} }  = \frac{c_{1} }{c_{2} }

Hence

2/a-b  =  3/a+b   =     7/3a +b-2

2/a-b  =  3/a+b

cross-multiply

3(a-b) = 2( a+b)

open the bracket

3a - 3b = 2a + 2b

collect like term

3a - 2a = 2b + 3b

a = 5b  -------------------------------------------(1)

Similarly

3/a+b   =     7/3a +b-2

cross-multiply

7(a+b)  = 3(3a+b -2)

7a + 7b = 9a + 3b -6

take all the variables to the left-hand side of the equation

7a - 9a+ 7b-3b =   -6

-2a + 4b = -6 ---------------------------------(2)

but a = 5b

substitute a= 5b in equation (2)   and solve for b

-2(5) + 4b = -6

-10  +  4b  = -6

add 10 to both-side of the equation

-10  + 10+ 4b  = -6+10

4b = 4

divide both-side of the equation by 4

b = 1

substitute b= 1 in equation (1)

a = 5b

a =5(1)

a=5

Therefore,   a= 5    and   b=1

8 0
3 years ago
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