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nadezda [96]
3 years ago
14

Find the value of x to make A||B

Mathematics
2 answers:
borishaifa [10]3 years ago
7 0
X=90 you have to make the two equations equal
SIZIF [17.4K]3 years ago
4 0

Answer:

x=90

Step-by-step explanation:

If the two liners were parallel, <1 and <4 would be congruent because they are corresponding angles. Since they are congruent, we can set them equal to each other

<1=<4

3x-160=x+20

Solve for x, by getting x by itself

Subtract x from both sides

2x-160=20

Add 160 to both sides

2x=180

Divide both sides by 2

x=90

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Simplify. Assume that no denominator is equal to zero. ([3^2]^3g^3h^4)^2
mariarad [96]

Answer:

531,441·g^6·h^8

Step-by-step explanation:

The operative rule of exponents is ...

(a^b)^c = a^(b·c)

Working from the inside out, according to the order of operations, we get ...

= (9^3·g^3·h^4)^2

= 729^2·g^(3·2)·h^(4·2)

= 531,441·g^6·h^8

7 0
3 years ago
Please help thx 10 poin
Annette [7]

Answer:

X = 55

Step-by-step explanation:

If the angel is 90:

75 + 90 = 165

165 divided by 3 = 55

7 0
2 years ago
Solve y+4x=12 3y=8-12x
attashe74 [19]
\left \{ {{y+4x=12} \atop {3y=8-12x}} \right. \\\\ \left \{ {{y=12-4x} \atop {3y=8-12x}} \right. \\\\3(12-4x)=8-12x\\\\36-12x=8-12x\\\\-12x+12x=8-36\\\\0\neq28\\\\There\ are\ no\ solutions.
6 0
3 years ago
Prove that a triangle with the sides a - 1 cm to root under a ​
vivado [14]

Question is Incomplete, Complete question is given below.

Prove that a triangle with the sides (a − 1) cm, 2√a cm and (a + 1) cm is a right angled triangle.

Answer:

∆ABC is right angled triangle with right angle at B.

Step-by-step explanation:

Given : Triangle having sides (a - 1) cm, 2√a and (a + 1) cm.  

We need to prove that triangle is the right angled triangle.

Let the triangle be denoted by Δ ABC with side as;

AB = (a - 1) cm

BC = (2√ a) cm

CA = (a + 1) cm  

Hence,

{AB}^2 = (a -1)^2 

Now We know that

(a- b)^2 = a^2+b^2 - 2ab

So;

{AB}^2= a^2 + 1^2 -2\times a \times1

{AB}^2 = a^2 + 1 -2a

Now;

{BC}^2 = (2\sqrt{a})^2= 4a

Also;

{CA}^2 = (a + 1)^2

Now We know that

(a+ b)^2 = a^2+b^2 + 2ab

{CA}^2= a^2 + 1^2 +2\times a \times1

{CA}^2 = a^2 + 1 +2a

{CA}^2 = AB^2 + BC^2

[By Pythagoras theorem]

a^2 + 1 +2a = a^2 + 1 - 2a + 4a\\\\a^2 + 1 +2a= a^2 + 1 +2a

Hence, {CA}^2 = AB^2 + BC^2

Now In right angled triangle the sum of square of two sides of triangle is equal to square of the third side.

This proves that ∆ABC is right angled triangle with right angle at B.

4 0
3 years ago
classify the polygon by its number of sides. state whether the polygon appears to be regular or not regular
UkoKoshka [18]

Answer: the correct answer is the third option




8 0
2 years ago
Read 2 more answers
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