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3 years ago

14

Can you guys help my brother please

1 answer:

GarryVolchara [31]3 years ago

7 0

A. 4
b. 8
c. 6th and 8th

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What is the estimate of forgive 6in by 4in

NNADVOKAT [17]

Find area of the semi circle.

The diameter is, half of that would be the radius, which is 3.

$\frac{\pi \cdot 3^2}{2}$ = 14.1

Find the area of the rectangle.

6 * 4 =24

Add the two areas together.

24 + 14.1 = 38.1

$38.1in^2$

6 0

3 years ago

tatuchka [14]

Asked and answered elsewhere.
brainly.com/question/10629871

How do you calculate it? You start by expressing the density in the units you have. Then you multiply by appropriate conversion factors to get to the units you want. Treat units as though they were any other variable. A value cancels that appears in both the numerator and denominator of a fraction.

$\dfrac{56.15\,kg}{0.222\,hh}\cdot \dfrac{1000\,g}{1\,kg}\cdot \dfrac{1\,pw}{1.55\,g}\cdot \dfrac{1\,hh}{238.5\,L}\cdot \dfrac{9.091\,L}{1\,pk}\\\\=\dfrac{56.15\cdot 1000\cdot 9.091\,pw}{0.222\cdot 1.55\cdot 238.5\,pk}\\\\ \approx6220\,\frac{pw}{pk}$

5 0

3 years ago

Find the distance between 6,-2 and 1,-2

lesantik [10]

The distance between (6,-2) and (1,-2) is 5.

8 0

3 years ago

Read 2 more answers

Julia enjoys shooting paper balls into the wastebasket across her office. She misses the first shot 50% of the time. When she mi

Marianna [84]

Answer:

a) Probability that Julia misses two shots in a row = $\frac{1}{2}\frac{1}{5} =\frac{1}{10}$

b) We can use the complement rule on this case. Let X the number of shoots successful, we want this probability:

$P(X \geq 1)$

And using the complement rule we have this:

$P(X \geq 1) = 1-P(X$

And P(X=0) correspond to the probability that Julia misses two shots in a row founded on part A so then we have:

$P(X\geq 1) = 1- \frac{1}{10}= \frac{9}{10}$

Step-by-step explanation:

Part a

For this case we know that Julia enjoys shooting paper balls into the basket across her office.

She misses the first shot 50% of the time.

Probability that Julia misses the first shot = $\frac{1}{2}$

When she misses on the first shot, she misses the second shot 20% of the time.

Probability that Julia misses the second shot = $\frac{1}{5}$

For this case we need to find the probability of missing two shots in a row

So we can multiple the two probabilities like this

Probability that Julia misses two shots in a row = $\frac{1}{2}\frac{1}{5} =\frac{1}{10}$

Part b

For this case we want probability of making at least one successful throw

And we can use the complement rule on this case. Let X the number of shoots successful, we want this probability:

$P(X \geq 1)$

And using the complement rule we have this:

$P(X \geq 1) = 1-P(X$

And P(X=0) correspond to the probability that Julia misses two shots in a row founded on part A so then we have:

$P(X\geq 1) = 1- \frac{1}{10}= \frac{9}{10}$

6 0

3 years ago

1. What is 20 1/2+ (- 34) − (7− 10 +12) simplified? Show work to support the answer.

Novay_Z [31]

Answer:

-45/2

Step-by-step explanation:

Step by step in the screenshots!!

6 0

3 years ago