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igomit [66]
3 years ago
7

What is the solution to the equation?

Mathematics
1 answer:
Serggg [28]3 years ago
5 0

Answer:

-63

Step-by-step explanation:

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The average number of points a basketball team scored for
Ganezh [65]
Average is

(2x + X+6)/3=63
(2x+x+6)= 189
3x+6=189
3x=183 61

X=61
Scores for the game are: 61, 61, and 67
3 0
3 years ago
.help work.............................math
e-lub [12.9K]

Answer:

Same

Step-by-step explanation:

x=2 y=2

x=3 y=3

x=4 y=4

x=5 y=5

and then graph it

3 0
3 years ago
I need a tutor who can answer more than 1 question.if not im sorry i have to end the session
nirvana33 [79]

Part A.

The area of a triangle is given by the product of its base and the height relative to that base.

Since these triangles have the same base b and same height h, they have the same area.

Part B.

The area of a rectangle or parallelogram is given by the product of base and height. Since these figures have the same base and height, they have the same area.

Part C.

These figures have different shapes, so we can't affirm that they have the same area.

Part D.

The height shown in the image is not the height relative to side b, therefore we can't affirm that the triangles have the same area.

4 0
1 year ago
Solve for x. 1 2 x + 3 2 (x + 1) − 1 4 = 5 A) 5 2 B) 15 4 C) 15 8 D) 17 8
Hitman42 [59]
Answer: x=-13/44 or -.2954
8 0
2 years ago
Read 2 more answers
The height h of a thrown object as a function of horizontal distance d that it has traveled is a quadratic function. An object i
omeli [17]

Answer:

  h(d) = (17/3249)(-d² +114d)

Step-by-step explanation:

For this purpose, it is convenient to translate and scale a quadratic parent function so it has the desired characteristics. We can start with the function ...

  f(x) = 1 -x² . . . . . . . has zeros at x = ±1 and a vertex at (0, 1)

We want to horizontally expand this function by a factor of 57, so we can replace x by x/57. We want to vertically scale it by a factor of 17, so the vertex is at (0, 17). Finally, we want to translate the function 57 m to the right, which requires replacing x with x-57. After these transformations, we have ...

  f(x) = 17(1 -((x-57)/57)²) = (17/3249)(-x²+114x)

Using the appropriate function name and variable, we have ...

  h(d) = (17/3249)(-d² +114d)

5 0
3 years ago
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