1.) 1.67×10 to the power of 9
2.) 1.133×10 to the power of -3
3.) 1.75×10 to the power of 9
4.) 2.64×10 to the power of 4
5.) 2.947×10 to the power of -6
6.) 4.24×10 to the power of 5
7.) 1.0207×10 to the power of 6
8.) 1.027×10 to the power of 5
If the center is at (0, 0) and the vertex is at (20, 0), then the distance, a, is the length from the center to the vertex, 20. The distance from the center to the focus is c. The distance from the center to the focus is 16, so c = 16. The formula we use to find the focus is
![c^2=a^2-b^2](https://tex.z-dn.net/?f=c%5E2%3Da%5E2-b%5E2)
. We have our c value and our a value, so we will sub in those to find b.
![16^2=20^2-b^2](https://tex.z-dn.net/?f=16%5E2%3D20%5E2-b%5E2)
and 256 = 400 - b^2. -b^2 = -144, so b = 12. There you go!
Answer:
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Related Questions
Subtract the following:
A) 18 rupees 9 paise from 75 rupees 80 paise.
B) 49 rupees 79 paise from 123 rupees 68 paise.
Answer
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Hint: Use decimal concept.
We know that, 1 rupee = 100 paise. We can reframe these questions as follows:
18 rupees 9 paise from 75 rupees 80 paise
18 rupees 9 paise can be represented as 18.09 rupees and 75 rupees 80 paise can be represented as 75.80 rupees. Now, on subtracting we’ll get,
75.80−18.09−−−−−− 57.71
Which means 57 rupees 71 paise
49 rupees 79 paise from 123 rupees 68 paise
49 rupees 79 paise can be represented as 49.79 rupees and 123 rupees 68 paise can be represented as 123.68 rupees. Now, on subtracting we’ll get,
123.68 −49.79−−−−−− 73.89
Which means 73 rupees 89 paise.
Note: We can also perform the subtraction by making all units the same that are paise and then subtract.
Answer:
shaded area = 601 mm²
Step-by-step explanation:
Area of rectangle = Length * Breadth
Area of first section = 12 * 16 = 192 mm²
Area of 2nd middle section = 8 * ( 16 - 10 ) = 48 mm²
Area of the bottom section = 19 * 19 = 361 mm²
Area of total therefore = 192 mm² + 48 mm² + 361 mm²
= 601 mm²