The value of the P(2 < X ≤ 4) is 0.14 if the probability of P(x =3) is 0.10 and P(x = 4) is 0.04.
<h3>What is a normal distribution?</h3>
It's the probability curve of a continuous distribution that's most likely symmetric around the mean. On the Z curve, at Z=0, the chance is 50-50. A bell-shaped curve is another name for it.
We have a probability distribution shown in the table:
P(2 < X ≤ 4)
We have to find the probability between 2 and 4
P(2 < X ≤ 4) = P(x =3) + P(x = 4)
From the table
P(x =3) = 0.10
P(x = 4) = 0.04
P(2 < X ≤ 4) = 0.10 + 0.04 = 0.14
Thus, the value of the P(2 < X ≤ 4) is 0.14 if the probability of P(x =3) is 0.10 and P(x = 4) is 0.04.
Learn more about the normal distribution here:
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Answer:
this question needs more detail
Step-by-step explanation:
I would just say 0 as the least possible length of the line
Call x the smallest of the three numbers, then:
x + (x+1) +(x+2) = -27
x + x + 1 + x + 2 = -27
3x+3 =-27
3x = -27 -3
3x = -30
x = -30/3 = -10
The three numbers are: -10, -9 and -8.
Answer:
8 m = width
28 m = length
Step-by-step explanation:
Let w = width
3w + 4 = length
P = 2w + 2l
= 2w + 2(3w + 4) = 72
2w + 6w + 8 = 72
8w + 8 = 72
8w = 64
w = 8 m = width
3w + 4 = 24 + 4 = 28 m = length
