3 years ago

Proportional relationships between x and y

Mathematics

1 answer:

maria [59]3 years ago

8 0

Answer:

The one on the left

Step-by-step explanation:

Since you're looking for a proportional relationship, the first one is the right answer. For all the values in that table, the y= 3/2x.

Hope this helps!

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What is 20÷1÷[(10÷5)÷2]

marysya [2.9K]

Answer: 20

Step-by-step explanation:

Follow order of operations (PEMDAS)

20÷1÷[(10÷5)÷2] Given

20÷1÷[(2)÷2] Do 10÷5 in parenthesis

20÷1÷[(1)] Do (2)÷2

20÷1 Do 1÷[(1)]

20 Do 20÷1, and that is your answer

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4 years ago

5. Solve the following system by graphing and identify the point of intersection.

Misha Larkins [42]

Answer:

Step-by-step explanation:

The answer should be the first one

A) (2, -4)

6 0

3 years ago

Please help me with this question helel

Vera_Pavlovna [14]

Answer:

$\frac{1}{2}$

Step-by-step explanation:

Given

tan x = $\sqrt{3}$ , then

x = $tan^{-1}$ ( $\sqrt{3}$ ) = 60° ← related acute angle

Since 180° < x < 270° and tan x > 0 then x is in third quadrant

x = 180° + 60° = 240°

and

sin(x - 210)°

= sin(240 - 210)°

= sin30°

= $\frac{1}{2}$

6 0

3 years ago

What is (2x)(X). You are multiplying 2x by x.

AnnZ [28]

Your answer would be 2x^2. Multiplying an x by an x makes it a squared variable.

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3 years ago

Read 2 more answers

Prove, Cosec2A + cot2A = cotA

elena-s [515]

Proved

Step-by-step explanation:

Cosec2A + cot2A = cotA

On Left hand-side

$Cosec2A + cot2A = \frac{1}{sin2A} +\frac{cos2A}{sin2A} \\\\\\$

$=\frac{1}{2sinAcosA} +\frac{2cos^2A-1}{2sinAcosA}$

$\frac{1+2cos^2A-1}{2sinAcosA} \\\\\\=\frac{2cos^22A}{2sinAcosA} \\\\=\frac{cosA}{sinA} \\\\\\=cotA$

Learn More

Trigonometric ratios: brainly.com/question/12462203

Keywords: Trigonometeric

#LearnwithBrainly

8 0

4 years ago