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Angelina_Jolie [31]
3 years ago
9

What limits the size of the cell?

Biology
1 answer:
nadezda [96]3 years ago
7 0
Yea what that person said
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The bones from an animal found at an archaeological dig have a C614 activity of 0.10 Bq per gram of carbon. The half-life of C61
erastova [34]

C14 is an isotope used in radiocarbon dating techniques to date organic matter remains. The age of these bones is approximately<u> 6890 years.</u>

<h3>What is Carbon 14?</h3>

Carbon 14, also known as radiocarbon, is a radioactive carbon isotope.

Isotopes are the atoms of the same element -carbon- that vary in neutrons and, hence, in their massic number. They are alternative forms of the same element.

The radioactive C14 nucleus contains 6 protons and 8 neutrons and has a half-life of 5730 years.

The term half-life is a reference. It means that an organism that has been dead for 5730 years has half the C14 amount or concentration than the same organism had when it was alive.

Knowing the half-life of an element is useful to determine the age of the dead matter.

C14 is used in radiocarbon dating techniques or methods to estimate the age of fossils. This is a reliable technique used for dating organic samples that are less than 50,000 years old.

<u>Available data</u>:

  • The half-life of C14 is 5730 years
  • Bones activity of 0.10 Bq per gram of carbon

To answer this question we can make use of the following equation

Ln (C14T₁/C14 T₀) = - λ T₁

Where,

  • C14 T₀ ⇒ Amount of carbon in a living body. We know, by bibliography, that living organism activity is 0.23 Bq per gram of carbon. So, C14 T₀ = 0.23 Bq/g
  • C14T₁ ⇒ Amount of carbon in the dead body. C14T₁ = 0.1 Bq/g
  • λ ⇒ radioactive decay constant = (Ln2)/T₀,₅
  • T₀,₅ ⇒ The half-life of carbon 14 = 5730 years
  • T₀ = Time when the organism was alive
  • T₁ = Age of bones

Let us first calculate the radioactive decay constant.

λ = (Ln2)/T₀,₅

λ = 0.693/5730

<u>λ = 0.0001209</u>

Now, let us calculate the first term in the equation

Ln (C14T₁/C14 T₀) = Ln (0.1/0.23) = Ln 0.4347 =<u> - 0.833</u>

Finally, let us replace the terms, clear the equation, and calculate the value of T₁.

Ln (C14T₁/C14 T₀) = - λ T₁

- 0.833 = - 0.0001209 x T₁

T₁ = - 0.833 / - 0.0001209

T₁ =  6889.99 ≅ <u>6890 years</u>

The bones are approximately<u> 6890 years.</u>

You can learn more about dating organic matter with carbon14 at

brainly.com/question/4149380

#SPJ1

6 0
3 years ago
In the 18th century, Carl Linnaeus published a system for classifying living things, which has been developed into the modern
Mazyrski [523]

Cavalier-Smith's model no longer separates prokaryotes and eukaryotes is the statement which differs from kingdom classification.

Explanation:

Cavalier-Smith in 1998 had reduced the kingdom numbers. The were brought down from 8 to 6. These are:

Animalia

Protozoa

fungi

plantae

chromista

bacteria

He divided eukaryotes into 6 kingdoms.  The kingdoms are refined for better classification.

While Carolus Linnaeus divided the organisms into two kingdoms

Animalia and plantae.

The five kingdom classification:

Monera (prpkaryotes)

Protista  ( unicellular eukaryotes)

fungi (multicellular decomposers)

plantae (multicellular producers)

Animalia (multicellular consumers)

It has drawbacks like in kingdom monera both autotrophs and heterotrophs  are included. Phylogeny is not explained in lower organisms of monera and protista. Virus is also in classification. Cavalier-Smith introduced a new kingdom called chromista which are single- celled or multicellular eukaryotic organisms as diatoms, algae, oomycetes and protozoans which perform photosynthesis.

6 0
3 years ago
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What do you think would happen if a trial of the experiment was done with frozen liver and potato?
Lerok [7]

Explanation:

They would react the same as with the vinegar and hydrogen peroxide at room temperature. They would react the same as with just the hydrogen peroxide.

4 0
3 years ago
Where does the water in lakes come from? Select the three correct answers.
baherus [9]
D: Surface-water runoff from rain
7 0
3 years ago
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The ability of an individual organism to survive and reproduce in its natural environment is called
Westkost [7]

Answer:

None of the Above.

Explanation:

The correct answer is fitness. The Theory of Evolution defines fitness as a result of the adaptations an organism has which increase its chance of survival.

5 0
2 years ago
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