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3 years ago

Find the product -1/2y(2y^3-8)

Mathematics

1 answer:

blondinia [14]3 years ago

3 0

Answer:

-y^4+4y

Step-by-step explanation:

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Can someone help me and walk me through it? Thank you:)

olya-2409 [2.1K]

First find the area of the triangle.

$\sf A=\dfrac{1}{2}bh$

$\sf A=\dfrac{1}{2}(6)(12)$

$\sf A=36cm^2$

ABCE is a parallelogram, this means that the area of triangle ABE is equal to the area of triangle EBC. The are of the entire trapezoid is 180 square centimeters, we already found the area of the triangle, so that leaves us with:

$\sf 180-36=144$

So the area of the entire parallelogram must be 144 square centimeters. So each half of the parallelogram must be equal to:

$\sf 144\div 2=\boxed{\sf 72cm^2}$

8 0

3 years ago

Find the solution to the system of equations,x+3y and 2x+4y=8

Sati [7]

Answer:

x = -7/3y + 8/3

y = -3/7x + 8/7

Step-by-step explanation:

First, set the equations next to each other to find x and y, I'll start with x:

x + 3y + 2x + 4y = 8

Combine like terms

3x + 7y = 8

Subtract both sides by 7y

3x + 7y - 7y = 8 - 7y

3x = 8 - 7y

I'll re-order the equation to make it easier to divide

3x = -7y + 8

Divide both sides by 3

3x / 3 = -7y + 8 /3

x = -7/3y + 8/3

If you need decimals just divide with a calculator

Now to find y:

We already combined like terms so we don't need to do that again...

3x + 7y = 8

Subtract both sides by 3x

3x - 3x + 7y = 8 - 3x

7y = 8 - 3x

I'll reorder the equation once again so the variable comes first

7y = -3x + 8

Divide both sides by 7

7y / 7 = -3x + 8 / 7

y = -3/7x + 8/7

Again, use a calculator to divide completely for decimals.

6 0

3 years ago

manny took a cab to a concert. if the cab fare was $14 and he want to leave a 15% tip how much will he pay total

padilas [110]

He would pay $2.10

I hope this helps! (:

4 0

3 years ago

I need to know what the answer is?<br>is it x,y,z,or w?

andrew-mc [135]

Answer:

Step-by-step explanation:

5 0

3 years ago

Let f(x) = 7x^2-5x+3 and g(x) = 2x^2+4x-6

Troyanec [42]

Answer:

$\large\boxed{A.\ f(x)+g(x)=9x^2-x-3}\\\boxed{B.\ f(x)-g(x)=5x^2-9x+9}\\\boxed{g(x)-f(x)=-5x^2+9x-9}$

Step-by-step explanation:

$f(x)=7x^2-5x+3,\ g(x)=2x^2+4x-6\\\\A:\\f(x)+g(x)=(7x^2-5x+3)+(2x^2+4x-6)\\f(x)+g(x)=7x^2-5x+3+2x^2+4x-6\qquad\text{combine like terms}\\f(x)+g(x)=(7x^2+2x^2)+(-5x+4x)+(3-6)\\f(x)+g(x)=9x^2-x-3$

$B:\\f(x)-g(x)=(7x^2-5x+3)-(2x^2+4x-6)\\f(x)+g(x)=7x^2-5x+3-2x^2-4x+6\qquad\text{combine like terms}\\f(x)-g(x)=(7x^2-2x^2)+(-5x-4x)+(3+6)\\f(x)+g(x)=5x^2-9x+9$

$C:\\g(x)-f(x)=(2x^2+4x-6)-(7x^2-5x+3)\\g(x)-f(x)=2x^2+4x-6-7x^2+5x-3\qquad\text{combine like terms}\\g(x)-f(x)=(2x^2-7x^2)+(4x+5x)+(-6-3)\\g(x)-f(x)=-5x^2+9x-9$

3 0

3 years ago