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pickupchik [31]
3 years ago
15

Ill give brainiest and 30 points

Mathematics
2 answers:
ArbitrLikvidat [17]3 years ago
6 0

Answer:

50 feet

Step-by-step explanation:

According to the Pythagorean theorem a^2+b^2=c^2 and if you put it into this equation it is 30^2 + 40^2 =50^2 which does work out

Kruka [31]3 years ago
4 0

I dont feel like typeing right now (its 50 )So here's my answer.

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Bill bought a new cellular phone. His monthly bill will be $34.99 each month which includes 100 minutes of use. Additional minut
velikii [3]
Let c be total cost, while m is the minutes above the base minutes;
C=34.99+0.23*m
C=34.99+0.23m
Note, m= total minutes - 100
3 0
3 years ago
What is the area of the trapezoid?<br> 5 cm<br> 14 cm<br> 5 cm<br> 10 cm
prisoha [69]

Answer:

A = 28 cm

Step-by-step explanation:

equation:

A = \frac{a + b}{2} h

A = \frac{4 + 10}{2} 4

solve:

A = \frac{14}{2}4

A = 7 x 4

A = 28 cm

8 0
3 years ago
Simplify square root 20 + square root 80
timama [110]

Answer:2\sqrt{5} \\+4\sqrt{5}



The square root of 20 simplified is 2\sqrt{5} \\

And the square root of 80 simplified is 4\sqrt{5}

So it would look like 2\sqrt{5} \\+4\sqrt{5}

8 0
3 years ago
The number of accidents per week at a hazardous intersection varies with mean 2.2 and standard deviation 1.4. The distribution o
DENIUS [597]

Answer:

33.36% probability that X is less than 2.

Step-by-step explanation:

The distribution is not normal, however, using the central limit theorem, it is going to be approximately normal. So

Central Limit Theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

Normal Probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 2.2, \sigma = 1.4, n = 9, s = \frac{1.4}{\sqrt{9}} = 0.467

(a) Suppose we let X be the mean number of accidents per week at the intersection during 9 randomly chosen weeks. What is the probability that X is less than 2?

This is the pvalue of Z when X = 2. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{2 - 2.2}{0.467}

Z = -0.43

Z = -0.43 has a pvalue of 0.3336.

33.36% probability that X is less than 2.

4 0
3 years ago
Please help thank you
Doss [256]

Answer:

x ≥ -4

Step-by-step explanation:

you subtract 10 on both sides to get x by itself. 6-10 = -4. since you already have x by itself you don’t have to do anymore

5 0
3 years ago
Read 2 more answers
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