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valkas [14]
3 years ago
5

The measures of three line segments are given in each set.

Mathematics
1 answer:
kolezko [41]3 years ago
6 0

Answer:

second option: 32.8 m, 48.2 m, 81.1 m  

Step-by-step explanation:

20.2 m + 20.4 m = 40.6 m.  which is bigger than 20.6 m. so yes  

32.8 m + 48.2 m = 81 m.  which is smaller than 81.1 m. so no  

12.8 m + 25.7 m = 38.5 m. which is bigger than 35.9 m. so yes  

35.6 m + 49.9 m = 85.5 m. which is bigger than 83.2 m. so yes

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Answer:

option c is correct.

Step-by-step explanation:

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WE need to simplify this equation.

Solve the parenthesis of each term.

=7\left\sqrt[3]{2x}\right-3\left\sqrt[3]{16x}\right-3\left\sqrt[3]{8x}\right

Now, We will find factors of the terms inside the square root

factors of 2: 2

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Putting these values in our equation:=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2X2X2X2 x}\right)-3\left(\sqrt[3]{2X2X2 x}\right)\\=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2X2X2} \sqrt[3] {2 x}\right)-3\left(\sqrt[3]{2X2X2} \sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2^3} \sqrt[3] {2 x}\right)-3\left(\sqrt[3]{2^3} \sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2x}\right)-3*2\left(\sqrt[3] {2 x}\right)-3*2\left(\sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2}\sqrt[3]{x}\right)-6\left(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)

Adding like terms we get:

=7\left(\sqrt[3]{2}\sqrt[3]{x}\right)-6\left(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right\\=(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)\\

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So, option c is correct

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3 years ago
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2(3-b)+5(b-3)^{2}

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