5 movie tickets cost $55. At this rate, what is the cost per ticket?

Mathematics

2 answers:

Mariana [72]2 years ago

4 0

Answer:

Step-by-step explanation:

55/5 equals 11

Snowcat [4.5K]2 years ago

4 0

Answer:

Step-by-step explanation:

55 divided by 5 equals 11

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Pls give answer for 9c thanks

harina [27]

Answer:

probability for 3 on a dice (P3) in one dice =

$\frac{1}{6}$

probability for even no. of a dice (Pe) =

$\frac{3}{6} = \frac{1}{2}$

Therefore, the probability of finding 3 on one dice and even on another (P) = P3 + Pe

$= \frac{1}{6} + \frac{1}{2} = \frac{1 + 3}{6} = \frac{4}{6} = \frac{2}{3}$

7 0

1 year ago

All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be

Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a student is proficient in reading but not mathematics and $A \cap B$ is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

$B = b + (A \cap B)$

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

$(A \cup B) + C = 1$