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3 years ago

Plzzzz help me

Mathematics

1 answer:

AVprozaik [17]3 years ago

4 0

y=kx

5=10k

k=10-5

k=5 is the correct answer

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I need help please ive been stuck on it

Andreas93 [3]

Answer:

$3,300

Step-by-step explanation:

The salary given falls in the third range, meaning it should get a 5.5% income tax on the $60,000.

5.5% = 0.055

0.055 * $60,000 = $3,300

Therefore, the state income tax owed on the provided salary is $3,300.

6 0

3 years ago

A pair of parallel lines is cut by a transversal. One of the angles formed measures 58°. Which statements about the other seven

Zanzabum

I had to draw this on paper to figure it out....4 angles measure 122.....and 4 angles measure 58

6 0

3 years ago

Read 2 more answers

Which statement is correct?

fiasKO [112]

Answer:

Ima guess c

Step-by-step explanation:

dont choose mines I guessed

8 0

3 years ago

Can someone solve this? also no explanation no brainliest

hram777 [196]

Answer:

Step-by-step explanation:

I don't really have a explanation but I hope this helped

7 0

3 years ago

Read 2 more answers

You are testing the claim that the proportion of men who own cats is smaller than the proportion of women who own cats. You samp

MariettaO [177]

Answer:

Given:You sample 160 men, and 25% own cats

You sample 120 women, and 20% own cats.

To Find : Find the test statistic, rounded to two decimal places.

Solution:

You sample 160 men, and 25% own cats.

No. of men have cats = $\frac{25}{100} \times 160$

= $40$

So, $n_1=160 , y_1=40$

You sample 120 women, and 20% own cats.

No. of women have cats = $\frac{20}{100} \times 120$

= $24$

So, $n_2=120 , y_2=24$

We will use Comparing Two Proportions

$\widehat{p_1}=\frac{y_1}{n_1}$

$\widehat{p_1}=\frac{40}{160}$

$\widehat{p_1}=0.25$

$\widehat{p_2}=\frac{y_2}{n_2}$

$\widehat{p_2}=\frac{24}{120}$

$\widehat{p_2}=0.2$

Let $p_1$ and $p_2$ be the probabilities of men having cat and women having cat receptively

$H_0:p_1=p_2\\H_a:p_1$

$\widehat{p}=\frac{y_1+y_2}{n_1+n_2} =\frac{24+40}{160+120}=0.228$

Formula of test statistic : $\frac{\widehat{p_1}-\widehat{p_2}}{\sqrt{\widehat{p}(1-\widehat{p})(\frac{1}{n_1}+\frac{1}{n_2})}}$

Substitute the values

test statistic : $\frac{0.25-0.2}{\sqrt{0.228(1-0.228)(\frac{1}{160}+\frac{1}{120})}}$

test statistic : $0.986$

So, test statistic is 0.986

8 0

4 years ago