the process by which plants use sunlight, water, and carbon dioxide to create oxygen and energy in the form of sugar.
Have a nice day <3
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Answer: Yes
Step-by-step explanation:
The math is right so you have nothing to worry about.
Answer:
1) The inverse of the function f(x)=2^x+6 is: f^(-1) (x)=log(x-6) / log(2)
2) The inverse of the functio f(x)=2^(x+6) is: f^(-1) (x) =log(x) / log(2) - 6
Solution:
1) f(x)=2^x+6
y=f(x)
y=2^x+6
Solving for x: Subtracting 6 both sides of the equation:
y-6=2^x+6-6
y-6=2^x
Applying log both sides of the equation:
log(y-6)=log(2^x)
Applying poperty of logarithm: log(a^b)=b log(a); with a=2 and b=x
log(y-6)=x log(2)
Dividing both sides of the equation by log(2)
log(y-6) / log(2)=x log(2) / log(2)
log(y-6) / log(2)=x
x=log(y-6) / log(2)
Changing "x" by "f^(-1) (x)" and "y" by "x":
f^(-1) (x)=log(x-6) / log (2)
2) f(x)=2^(x+6)
y=f(x)
y=2^(x+6)
Solving for x: Applying log both sides of the equation:
log(y)=log(2^(x+6))
Applying poperty of logarithm: log(a^b)=b log(a); with a=2 and b=x+6
log(y)=(x+6) log(2)
Dividing both sides of the equation by log(2)
log(y) / log(2)=(x+6) log(2) / log(2)
log(y) / log(2)=x+6
Subtracting 6 both sides of the equation:
log(y) / log(2) - 6 = x+6-6
log(y) / log(2) - 6 = x
x=log(y) / log(2) -6
Changing "x" by "f^(-1) (x)" and "y" by "x":
f^(-1) (x)=log(x) / log (2) - 6
Answer: C - fog(2) = 1
Step-by-step explanation: x^3 and x-1 make x
^3-3x^2+3x-1.
Make those into a root by factoring the x^3 and 3x^2+3x-1
Cannot be simplified anymore so (x-1)(x^2-2x+1)
x^2 can be simplifed to make (x-1)(x-1)
So, you get (x-1)(x-1)(x-1).
Answer can be simplified to x=1 or fog(2) = 1
Hope you have the answer you are looking for and have a nice day!
Subtract 250-50 which equals 200 and then multiply it by 3 which is 600
