Directions: Using the image and the scenario provided in the trajectory scenario activity Question #1, determine the trajectory
the bullet traveled. Drawings are not to scale. Question #1. A bullet from a sniper struck and killed a controversial political figure who was waiting in a nearby car as a passenger. Crime scene investigators are unsure what floor of the building the shot came from. The first floor of the hotel is 25 ft. high. Each subsequent floor is 15 ft. tall. Entry point on car window above horizontal = 12 in. Distance from car window to victim = 42 in. Distance from building to victim’s car = 350 ft. Using the measurements from the scene, determine what floor of the building the shooter came from. Tips: Convert units to feet, Complete ratio to find the height of the shooter in feet. To determine the floor number from feet: 25 + 15x, The floor number = add one to x. Which means the shooter was on which floor? a 5 b 6 c 7 d 8
1 answer:
Answer: 6 floors
Step-by-step explanation: Given that:
The first floor height = 25ft
Where each subsequent floor is 15 ft. tall.
Entry point on car window above horizontal = 12 in.
Distance from car window to victim = 42 in.
Distance from building to victim’s car = 350 ft.
Using similarity in angle method, we have
(25 + 15x)/350 = 12 in/42 in
Convert inches to feet by dividing the value by 12
(25 + 15x)/350 = 1/3.5
Cross multiply
3.5(25 + 15x) = 350
87.5 + 52.5x = 350
52.5x = 350 - 87.5
52.5x = 262.5
X = 262.5/52.5
X = 5
Therefore,
The floor number = 1 + 5 = 6 floors
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Answer:
We conclude that the initial value and y-intercept are the same thing on a graph.
Please check the attached graph of the equation y = 2x+1.
Step-by-step explanation:
We know that the initial value on a graph is basically the out-put value y of the point where the line meets or crosses the y-axis.
In other words, the initial value is the y-value or output of the point at x = 0
For example,
Let the equation
y = 2x+1
substitute x = 0
y = 2(0)+1
y = 0+1
y = 1
Thus, the initial value of the equation y = 2x+1 is: y = 1
Please check the attached graph of the equation y = 2x+1.
It is clear from the graph that at x = 0, the value of y = 1.
Thus, at y = 1, the line meets the y-axis.
Hence, the initial value of the line is: y = 1
Similarly, we know that the value of the y-intercept can be determined by setting x = 0 and determining the corresponding value of y.
For example,
Let the equation
y = 2x+1
substitute x = 0
y = 2(0)+1
y = 0+1
y = 1
Thus, the y-intercept of y = 2x+1 is y = 1.
Please check the attached graph of the equation y = 2x+1.
It is clear from the graph that at x = 0, the value of y = 1.
Therefore, the y-intercept of y = 2x+1 is y = 1.
Conclusion:
Therefore, we conclude that the initial value and y-intercept are the same thing on a graph.
Please check the attached graph of the equation y = 2x+1.
