This is a system of equations problem. Set up the 2 equations like so: If the angles are complementary then they add up to 90, therefore, a + b = 90. We also know that a is 16 more than b. The word "is" means equals and "more" is addition. Therefore, a is 16 more than b is "a = b + 16". Now sub in that value of a (b + 16) into the first equation and solve for b. Then back-substitute to solve for a. (b + 16) + b = 90 so 2b + 16 = 90 and 2b = 74. So b = 37. If b = 37, then a + 37 = 90 and a = 53. Check yourself to make sure that 37 + 53 add up to equal 90 (they do, just get used to checking yourself for accuracy).
1.you add up all of the numbers you have
2.subtract the number you get from the average
3.if you know how many numbers there is then you know how many numbers you need to get
4.divide the number you got from the problem you made from step 1 & 2
5.what numbers you get from that are the numbers you needed to find
Answer:
the graph on the bottom left
Step-by-step explanation:
outliers are points that are away from the cluster of points in the bottom left graph all of the points are grouped up therefor the bottom left graph is the correct answer
Break x⁴ into x³ and x¹, watch the step below
![\sqrt[3]{ x^{4} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20x%5E%7B4%7D%20%7D%20)
![= \sqrt[3]{ x^{3+1} }](https://tex.z-dn.net/?f=%3D%20%5Csqrt%5B3%5D%7B%20x%5E%7B3%2B1%7D%20%7D%20)
Remember that

Use the property above to simplify the root
![= \sqrt[3]{ x^{3+1} }](https://tex.z-dn.net/?f=%3D%20%5Csqrt%5B3%5D%7B%20x%5E%7B3%2B1%7D%20%7D%20)
![=(\sqrt[3]{ x^{3} })( \sqrt[3]{x^{1}} )](https://tex.z-dn.net/?f=%3D%28%5Csqrt%5B3%5D%7B%20x%5E%7B3%7D%20%7D%29%28%20%5Csqrt%5B3%5D%7Bx%5E%7B1%7D%7D%20%29)
= x ∛x
The answer is first option