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sergiy2304 [10]
3 years ago
6

HELP!!!! An 80% confidence interval for a proportion is found to be (0.12,0.18). What is the sample proportion?

Mathematics
2 answers:
jeka57 [31]3 years ago
8 0

Answer: .15

Step-by-step explanation:

Just did it

Jobisdone [24]3 years ago
4 0

Answer: 0.15

Step-by-step explanation:

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Plssss help due today
asambeis [7]

160-80 = 80

80/2 = 40


angle BCD = 40 degrees


please mark brainliest

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4 years ago
A hot air balloon descends from an altitude of 2,000 feet at a constant rate of 90 feet per minute. The graph shows the altitude
liberstina [14]

Answer:

y=90x+2,000

Step-by-step explanation:

90 is the rate of change because the hot air balloon descends 90 feet per minute.

And 2,000 is the starting point because the hot air balloon started the descent at 2,000 feet.

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3 years ago
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The grace period is the _____. maximum amount of money you can charge on the credit card time before the credit card company sta
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5 0
4 years ago
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What is 2 times 4 by the power of 10
goblinko [34]

Answer: 1073741824 because 2x4 is 8 and 8 to the power of 10 is 1073741824

4 0
3 years ago
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Suppose a marketing company wants to determine the current proportion of customers who click on ads on their smartphones. It was
andrezito [222]

Answer:

The 92% confidence interval for the true proportion of customers who click on ads on their smartphones is (0.3336, 0.5064).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 100, p = 0.42

92% confidence level

So \alpha = 0.08, z is the value of Z that has a pvalue of 1 - \frac{0.08}{2} = 0.96, so Z = 1.75.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.42 - 1.75\sqrt{\frac{0.42*0.58}{100}} = 0.3336

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.42 - 1.75\sqrt{\frac{0.42*0.58}{100}} = 0.5064

The 92% confidence interval for the true proportion of customers who click on ads on their smartphones is (0.3336, 0.5064).

4 0
4 years ago
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