My last math question! I need help. I'm not good at math so I'm relying on who ever do this to do so correctly!!!!

In △ABC, AB = 13.2m,

luda_lava [24]

Answer:

(i) ∠ABH = 14.5°

(ii) The length of AH = 4.6 m

Step-by-step explanation:

To solve the problem, we will follow the steps below;

(i)Finding ∠ABH

first lets find <HBC

<BHC + <HBC + <BCH = 180° (Sum of interior angle in a polygon)

46° + <HBC + 90 = 180°

<HBC+ 136° = 180°

subtract 136 from both-side of the equation

<HBC+ 136° - 136° = 180° -136°

<HBC = 44°

lets find <ABC

To do that, we need to first find <BAC

Using the sine rule

$\frac{sin A}{a}$ = $\frac{sin C}{c}$

A = ?

a=6.9

C=90

c=13.2

$\frac{sin A}{6.9}$ = $\frac{sin 90}{13.2}$

sin A = 6.9 sin 90 /13.2

sinA = 0.522727

A = sin⁻¹ ( 0.522727)

A ≈ 31.5 °

<BAC = 31.5°

<BAC + <ABC + <BCA = 180° (sum of interior angle of a triangle)

31.5° +<ABC + 90° = 180°

<ABC + 121.5° = 180°

subtract 121.5° from both-side of the equation

<ABC + 121.5° - 121.5° = 180° - 121.5°

<ABC = 58.5°

<ABH = <ABC - <HBC

=58.5° - 44°

=14.5°

∠ABH = 14.5°

(ii) Finding the length of AH

To find length AH, we need to first find ∠AHB

<AHB + <BHC = 180° ( angle on a straight line)

<AHB + 46° = 180°

subtract 46° from both-side of the equation

<AHB + 46°- 46° = 180° - 46°

<AHB = 134°

Using sine rule,

$\frac{sin 134}{13.2}$ = $\frac{sin 14.5}{AH}$

AH = 13.2 sin 14.5 / sin 134

AH≈4.6 m

length AH = 4.6 m

8 0

2 years ago

The effect of exposure to high-density automobile traffic either as a bicyclist or pedestrian was compared to minimal or no expo

Ber [7]

The option B is correct option. Thus, the Study design is used is a Case control study.

According to the statement

we have given that the incident cases of MI diagnosed in the emergency rooms of several hospitals is 500 and compared to 1,000 other subjects who visited the same emergency rooms for reasons other than cardiovascular and respiratory diseases.

And we have to find that the all these type of reports are formed which study method in medical science.

So, For this purpose, we know that the

A case control study is a study that compares two groups of people: those with the disease or condition under study (cases) and a very similar group of people who do not have the disease or condition (controls).

This study is perfectly match with the given condition.

So,

Case-control study is used in it by the below written way:

The study design relies on hospital-based recruitment of cases (persons with an MI) and controls (other patients in the emergency room who did not have cardiovascular and respiratory diseases which may be associated with air pollution). The exposure under investigation is a time-dependent measure of exposure to high-density automobile traffic in the days preceding the emergency room visit.

So, The option B is a correct option. The Study design is used is a Case control study.

Learn more about Case control study here

brainly.com/question/24087096

Disclaimer: This question was incomplete. Please find the full content below.

Question:

The effect of exposure to high-density automobile traffic either as a bicyclist or pedestrian was compared to minimal or no exposure to automobile traffic. It is hypothesized that direct exposure to automobile traffic has an effect on acute myocardial infarction (MI). This association was studied with 500 incident cases of MI diagnosed in the emergency rooms of several hospitals and compared to 1,000 other subjects who visited the same emergency rooms for reasons other than cardiovascular and respiratory diseases. All subjects were asked to report the amount of time that they spent exposed to high-density traffic over the past month prior to their hospital visit.

What type of study design is this?

A) Cross-sectional

B) Case-control

C) Retrospective cohort

D) Prospective cohort

E) Randomized clinical trial

#SPJ4

5 0

1 year ago

Find the mean 35 40 12 16 25 10

ruslelena [56]

Answer: Mean = 23