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yanalaym [24]
3 years ago
7

(4x+5)(4x−5) I'm stuck can someone please help me ​

Mathematics
2 answers:
Marizza181 [45]3 years ago
5 0

Answer:6small2−25

Step-by-step explanation:

Vesnalui [34]3 years ago
3 0

Answer:

16x² - 25

Step-by-step explanation:

(4x+5)(4x−5)

16x² - 20x + 20x - 25

16x² - 25

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Solve for www. Give an exact answer in simplified form. 53w+13 < 56w + 16
ki77a [65]

The solution will be:  w>-1

<em><u>Explanation</u></em>

The given inequality is:   53w+13 < 56w + 16

First we will subtract 56w from both sides. So.....

53w+13-56w

Now we will subtract 13 from both sides. So.....

-3w

Then we need to divide both sides by -3. As here we are <u>dividing the inequality by a negative number, so we need to switch the inequality symbol</u>. So, we will get.......

\frac{-3w}{-3}>\frac{3}{-3}\\ \\ w>-1

Thus, the solution will be:  w>-1

5 0
3 years ago
Compare using &lt;, &gt; or =<br> -15_____-21<br><br> A. &lt;<br> B. &gt;<br> C. =
Scilla [17]

the answer is -15 > -21

7 0
3 years ago
PLEASE ANSWER TODAY<br><br><br> Express a 10/3 b 7/3 in simplified radical form.
34kurt
I guess this is what you mean     3√a^10      and 3√b^7
4 0
3 years ago
Jamar's teacher told him that one of the reasons he gave on the proof below was incorrect. Which reason did he make the mistake
Kamila [148]

Answer:

Reason given in step 2. is incorrect. It should read; "Distributive Property."

Step-by-step explanation:

The reason given to go from :

2 (3x +4) = 56  to 6x + 8 = 56

is NOT "Multiplication Property of Equality" because one is not multiplying both sides of the equality by a number. The property that is being used is the Distributive Property on the left side of the equation in order to remove the grouping symbols (parenthesis) performing the implied multiplication of the external factor times each term of the binomial in parenthesis.

8 0
3 years ago
What is the solution of the equation when solved using the quadratic formula?<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D%20%2B
Artemon [7]

Answer:

x=\pm2i\sqrt{5}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Standard Form: ax² + bx + c = 0
  • Quadratic Formula: x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}

<u>Algebra II</u>

  • Imaginary Numbers: √-1  = i

Step-by-step explanation:

<u>Step 1: Define Equation</u>

x² + 20 = 0

<u>Step 2: Identify Variables</u>

a = 1

b = 0

c = 20

<u>Step 3: Find roots </u><em><u>x</u></em>

  1. Substitute:                    x=\frac{-0\pm\sqrt{0^2-4(1)(20)} }{2(1)}
  2. Exponents:                   x=\frac{-0\pm\sqrt{0-4(1)(20)} }{2(1)}
  3. Multiply:                        x=\frac{-0\pm\sqrt{0-80} }{2}
  4. Subtract:                       x=\frac{\pm\sqrt{-80} }{2}
  5. Factor:                          x=\frac{\pm\sqrt{-1} \sqrt{80} }{2}
  6. Simplify:                        x=\frac{\pm4i\sqrt{5} }{2}
  7. Divide:                          x=\pm2i\sqrt{5}
6 0
2 years ago
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