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solmaris [256]
3 years ago
11

If a car dealership buy as car for $9000, and wants to make a 45% profit, how much do they need to sell the car for? ​

Mathematics
1 answer:
Degger [83]3 years ago
6 0

Answer:

A car dealership needs $13050 to sell the car to earn the 45% profit if a car dealership buys a car for $9000.

Step-by-step explanation:

Car cost = $9000

Profit percentage = 45% profit

Thus,

Profit amount = 45% of 9000

                       = 45/100 × 9000

                       = 0.45 × 9000

                       = $4050

In order to determine how much a car dealership needs to sell the car to earn the 45% profit, all we need is to add the profit amount i.e. $4050, and the car cost i.e. $9000.

i.e.

Car cost + Profit amount = $9000 + $4050

                                         = $13050

Therefore, a car dealership needs $13050 to sell the car to earn the 45% profit if a car dealership buys s car for $9000.

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Answer:

A)

k=0

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C)

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Step-by-step explanation:

We are given the function:

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A)

Given that h(1) = 20, we want to find <em>k</em>.

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B)

Given that h(1) = 40, we want to find 2<em>k</em> + 1.

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\displaystyle (40) = 20e^{k(1)}

Simplify:

\displaystyle 2 = e^{k}

We can take the natural log of both sides:

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\displaystyle k = \ln 2

Therefore:

2k+1 = 2\ln 2+ 1 \approx 2.3863

C)

Given that h(1) = 10, we want to find <em>k</em> - 3.

Again, this meas that <em>h</em>(x) = 10 when <em>x</em> = 1. Substitute:

\displaystyle (10) = 20e^{k(1)}

Simplfy:

\displaystyle \frac{1}{2} = e^k

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