Answer:
When you reflect across the x-axis, the x coordinate stays the same. When you reflect across the y-axis, the x coordinate becomes opposite. When you reflect over the origin, both coordinates become opposite.
Step-by-step explanation:
When you look at the coordinate plane, the x-axis is horizontal (side to side) and the y-axis is vertical (up and down). If you reflect across the x-axis, then you are mirroring (flipping) the object over the horiontal line, which means your x value stays the same. If you reflect across the y-axis, you are mirroring (flipping) the object over the vertical line, which means your y value stays the same and the x value must become opposite. When you cross the origin, you are going diagonal across the coordinate plane, which means both the x and y values will become opposite.
Answer:
128
Step-by-step explanation:
<em><u>The equation for the product of -2 and -30 gives 60 is:</u></em>

<em><u>Solution:</u></em>
Given that, The product of -2 and -30 gives 60
We have to write the sentence as equation
It includes operations such as addition, subtraction, multiplication and division.
From given statement,
The product of -2 and -30 gives 60
Here, "product" means multiplication
Therefore, -2 multiplied with -30 gives 60
Which is written as equation as,

Thus the given sentence is translated into equation
Answer:
30 pages
Step-by-step explanation:
Knowing she wrote 12 pages in 4 hours, we can do 12/4 to get 3 pages per hour. Multiply 3 pages by the 6 hours she spends writing and you get 18 pages in 6 hours. Add 12 pages and 18 pages and you have 30 pages.
<u>Here are your fill-ins:</u>
r = 1 is a zero, so (r-1) is a factor.
r = -1 is a zero, so (r+1) is a factor.
The remainders from synthetic division are 0 each time.
See the attachment for the synthetic division numbers.
_____
The reduced quadratic is ...
... x² -6x +13 = 0
Solving by completing the square, we have ...
... (x -3)² = -4
... x = 3 ± 2i
_____
The quadratic formula would tell you ...
... x = (-(-6) ± √((-6)² -4(1)(13)))/(2·1) = (6±√-16)/2 = 3±2i