How much is 7 cups in pints Write your answer as a whole or mixed number in simplest form

Construct a 99% confidence interval for the population mean, mu. Assume the population has a normal distribution. A group of 1

Zarrin [17]

Answer:

99% confidence interval for the population mean is [19.891 , 24.909].

Step-by-step explanation:

We are given that a group of 19 randomly selected students has a mean age of 22.4 years with a standard deviation of 3.8 years.

Assuming the population has a normal distribution.

Firstly, the pivotal quantity for 99% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean age of selected students = 22.4 years

s = sample standard deviation = 3.8 years

n = sample of students = 19

$\mu$ = population mean

Here for constructing 99% confidence interval we have used t statistics because we don't know about population standard deviation.

So, 99% confidence interval for the population mean, $\mu$ is ;

P(-2.878 < $t_1_8$ < 2.878) = 0.99 {As the critical value of t at 18 degree of

freedom are -2.878 & 2.878 with P = 0.5%}

P(-2.878 < $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ < 2.878) = 0.99

P( $-2.878 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X - \mu}$ < $2.878 \times {\frac{s}{\sqrt{n} } }$ ) = 0.99

P( $\bar X -2.878 \times {\frac{s}{\sqrt{n} }$ < $\mu$ < $\bar X +2.878 \times {\frac{s}{\sqrt{n} }$ ) = 0.99

99% confidence interval for $\mu$ = [ $\bar X -2.878 \times {\frac{s}{\sqrt{n} }$ , $\bar X +2.878 \times {\frac{s}{\sqrt{n} }$ ]

= [ $22.4 -2.878 \times {\frac{3.8}{\sqrt{19} }$ , $22.4 +2.878 \times {\frac{3.8}{\sqrt{19} }$ ]

= [19.891 , 24.909]

Therefore, 99% confidence interval for the population mean is [19.891 , 24.909].

6 0

3 years ago

What is the lcm lcm of 8,9 and 10

vivado [14]

Answer:

360

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Can someone help? 25 points

denpristay [2]

Answer:

the answer is 157

Step-by-step explanation:

i had a test with the same question, i promise its right :)

7 0

3 years ago

Write 2350 million in standard form

AleksAgata [21]

we know that

Standard Form is also known as Scientific Notation, is a method of writing numbers that accommodates value excessively large or small to be suitably written in Standard Decimal Notation

in this problem we have

$2,350\ million$

Remember that

$1\ million=1,000,000$

so

$2,350\ million=2,350*1,000,000=2,350,000,000$

convert to standard form

$2,350,000,000=2.35*10^{9}$

therefore

the answer is

$2.35*10^{9}$

8 0

3 years ago

Read 2 more answers

Please help me 5-7g-9=

timofeeve [1]

Answer:

4 - 7g

Step-by-step explanation:

Combine like terms: 5 - 9 - 7g = -4 - 7g (answer)

6 0

3 years ago