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mamaluj [8]
2 years ago
6

Two candidates ran for class president. The candidate that won received 80% of the 250 total votes. How many votes did the winni

ng candidate receive?
Mathematics
2 answers:
Aleks [24]2 years ago
6 0

Answer:

200 votes

Step-by-step explanation:

250*.8=200

Kobotan [32]2 years ago
5 0

Answer:

The winning candidate recieved 200 votes.

Step-by-step explanation:

80%=0.8

250*0.8=200

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Lisa typed a 165-word paragraph in three minutes. Use the ratio table to
JulsSmile [24]

Answer:

1 minute

Step-by-step explanation:

We can see that Lisa types 165 words in 3 mins.

So she types 55 words in 1 minute.

How did I work that out?

Well, all you really do is \frac {165}{3} which is equal to \frac{55}{1} if you divide top and bottom by 3. Anything divided by 1 is itself.

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2 years ago
I’ll give brainliest HELO ASAP PLZ!!
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Answer:

a

Step-by-step explanation:

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3 years ago
Read 2 more answers
The mean points obtained in an aptitude examination is 159 points with a standard deviation of 13 points. What is the probabilit
Korolek [52]

Answer:

0.4514 = 45.14% probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 159, \sigma = 13, n = 60, s = \frac{13}{\sqrt{60}} = 1.68

What is the probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled?

This is the pvalue of Z when X = 159+1 = 160 subtracted by the pvalue of Z when X = 159-1 = 158. So

X = 160

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{160 - 159}{1.68}

Z = 0.6

Z = 0.6 has a pvalue of 0.7257

X = 150

Z = \frac{X - \mu}{s}

Z = \frac{158 - 159}{1.68}

Z = -0.6

Z = -0.6 has a pvalue of 0.2743

0.7257 - 0.2743 = 0.4514

0.4514 = 45.14% probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled

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3 years ago
Answer quickly, please. I need this. I will give brainliest to whoever answers first. You also get 25 points for this
sukhopar [10]
** DISCLAMIER** am not completely sure. Please do not use my answer unless you are very desperate.

since O,R correspond with A,N I think you half F on each side and add it to 11.2 so
10 divided by 2 = 5
7 is already half.
5 + 7 is 12
12 + 11.2 = 23.2

IF THIS IS WRONG TRY 17
reason for 17:
10 + 7 = 17
If you look at both lines they look the same length as A, N.
3 0
3 years ago
A typical cup of coffee contains about 100 mg of caffeine and every hour approximately 16% ofthe amount of caffeine inthe body i
Over [174]

Answer:

a) \frac{dC}{dt} = rC

And for this case we can rewrite the model like this:

\frac{dC}{C} = r dt

If we integrate both sides we got:

ln C = rt + k

If we use exponentials for both sides we got:

C = e^{rt} e^k = C_o e^{rt}

For this case C_o = 100 mg and r = -0.16

So then our model would be given by:

C(t) = 100 e^{-0.16 t}

Where t represent the number of hours

b) C(5) = 100 e^{-0.16*5}= 44.9329

Step-by-step explanation:

Part a

For this case we can assume the proportional model given by:

\frac{dC}{dt} = rC

And for this case we can rewrite the model like this:

\frac{dC}{C} = r dt

If we integrate both sides we got:

ln C = rt + k

If we use exponentials for both sides we got:

C = e^{rt} e^k = C_o e^{rt}

For this case C_o = 100 mg and r = -0.16

So then our model would be given by:

C(t) = 100 e^{-0.16 t}

Where t represent the number of hours

Part b

For this case we can replace the value t=5 into the model and we got:

C(5) = 100 e^{-0.16*5}= 44.9329

7 0
3 years ago
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