1 mol = 6.022 x 10²³ atoms
In order to find how many atoms, dimly multiply the amount of moles you have by 6.022 x 10²³ or Avogadro's number.
So you have 1.75 mol CHC1₃ x (6.022x10²³) = 1.05385 x 10²⁴ atoms of CHCl₃
But now you have to round because of the rules of significant figures so you get 1.05 x 10²⁴ atoms of CHCl₃
Answer:
41.6 moles
Explanation:
We apply the Ideal Gases Law to solve this:
P . V = n . R . T
Volume is 1m³ but we need to convert to dm³ (L), because the units of R
1m³ . 1000 dm³/1m³ = 1000 dm³ → 1000L
Now we replace → 1 atm . 1000 L = n . 0.082L.atm/mol.K . 293.15K
(1 atm . 1000 L) / (0.082L.atm/mol.K . 293.15K) = n → 41.6 moles
Answer:
Explanation:
To solve the problem, we must know the kind of compounds we are dealing with.
For the first compound, P1 and second compound P2:
N O N O
Mass percent 64.17 35.73 47.23 52.79
Atomic mass 14 16 14 16
Number of
moles 64.17/14 35.73/16 47.23/14 52.79/16
4.58 2.23 3.37 3.30
Simplest
ratio 4.58/2.23 2.23/2.23 3.37/3.30 3.3/3.3
2 1 1 1
P1 compound is N₂O
P2 compound is NO
These are the compounds,
In N₂O = 28:16
NO = 14:16
This is the ratio of nitrogen to a fixed mass of oxygen for the two compounds.
Answer:
B The water at the bottom of the lake will never freeze
Explanation:
Its simple