The reaction between butanoic acid and ethanol is:
CH3CH2CH2COOH + CH3CH2OH → CH3CH2CH2COOCH3CH2 + H2O
Based on the reaction stoichiometry:
1 mole of butanoic acid forms 1 mole of ethyl butyrate
Now,
Molar mass of Butanoic acid = 88.0 g/mol
Given mass of butanoic acid = 7.20 g
Therefore, # moles of butanoic acid reacted = 7.20/88.0 = 0.0818 moles
# moles of ethyl butyrate formed = 0.0818 moles
Molar mass of ethyl butyrate = 116 g/mol
Mass of ethyl butyrate synthesized = 0.0818 * 116 = 9.49 g
Answer:
The sum of an object's potential and kinetic energies is called the object's mechanical energy. As an object falls its potential energy decreases, while its kinetic energy increases. The decrease in potential energy is exactly equal to the increase in kinetic energy
Thank you and please rate me as brainliest as it will help me to level up
The molarity of the solution of H₃PO₄ needed to neutralize the KOH solution is 0.35 M
<h3>Balanced equation </h3>
H₃PO₄ + 3KOH —> K₃PO₄ + 3H₂O
From the balanced equation above,
- The mole ratio of the acid, H₃PO₄ (nA) = 1
- The mole ratio of the base, KOH (nB) = 3
<h3>How to determine the molarity of H₃PO₄ </h3>
- Volume of acid, H₃PO₄ (Va) = 10.2 mL
- Molarity of base, Ca(OH)₂ (Mb) = 0.2 M
- Volume of base, Ca(OH)₂ (Vb) = 53.5 mL
- Molarity of acid, H₃PO₄ (Ma) =?
MaVa / MbVb = nA / nB
(Ma × 10.2) / (0.2 × 53.5) = 1 / 3
(Ma × 10.2) / 10.7 = 1 / 3
Cross multiply
Ma × 10.2 × 3 = 10.7
Ma × 30.6 = 10.7
Divide both side by 30.6
Ma = 10.7 / 30.6
Ma = 0.35 M
Learn more about titration:
brainly.com/question/14356286
#SPJ1
Answer:
The deprotonated organic acid (RCO2-) and protonated organic base (RNH3+) go into the aqueous layer because Organic compounds that are neither acids or bases do not react with either NaOH or HCl and, therefore remain more soluble in the organic solvent and are not extracted.
Explanation:
Qualitative properties are properties that are observed and can generally not be measured with a numerical result. They are contrasted to quantitative properties which have numerical characteristics.
