Answer: 67 degrees
Step-by-step explanation:
Answer:
2.5%
Step-by-step explanation:
It is given that:
lifespans of seals in a particular zoo are normally distributed. The average seal lives 13.8 years and the standard deviation is 3.2 years.
We want to use the empirical rule to estimate the probability of a seal living longer than 7.4
Let's calculate the z-score of 7.4 using
![z = \frac{x - \mu}{ \sigma}](https://tex.z-dn.net/?f=z%20%3D%20%20%5Cfrac%7Bx%20-%20%20%5Cmu%7D%7B%20%5Csigma%7D%20)
![z = \frac{7.4 - 13.8}{3.2}](https://tex.z-dn.net/?f=z%20%3D%20%20%5Cfrac%7B7.4%20-%2013.8%7D%7B3.2%7D%20)
![z = - 2.00](https://tex.z-dn.net/?f=z%20%3D%20%20-%202.00)
According to empirical rule, 95% of the distribution is within 2 standard deviations, i.e (-2 to 2)
So from (-2 to 0), we would have 47.5%
Since we are looking for the area to the left of -2.00 we subtract this from 50%
to get 2.5%
It's A. 8x8 is 64. Therefore, 8cm is correct.