Answer:
The letter "x" is often used in algebra to mean a value that is not yet known. It is called a "variable" or sometimes an "unknown". In x + 2 = 7, x is a variable, but we can work out its value if we try! A variable doesn't have to be "x", it could be "y", "w" or any letter, name or symbol.
Step-by-step explanation:
9.1/3575
use long division like this
_<u>0.</u>_________
3575|91.000000
we find how many of 3575 fit into the 91
it's too big so we go farther
how many 3575 go into 910
too big so we go farther
how many 3575 go into 9100
the answer is 2 so put that in the correct place and mulitply that and put that in the correct place. then we subtract
_<u>0.</u><u>02</u>_________
3575|91.000000
-<u>71.50</u>
19.50
bring down the next number
find how many go into 19.500
the answe ris 5
_<u>0.</u><u>02</u><u>5</u>_________
3575|91.000000
-<u>71.50</u>
19.500
-<u>17.875</u>
1.625
bring down he next zero ( I fast forward and skip steps for convinience)
__
_<u>0.</u><u>02</u><u>5</u><u>455</u>_________
3575|91.000000
-<u>71.50</u>
19.500
-<u>17.875</u>
1.6250
-<u>1.4300</u>
.19500
-<u>.17875
</u> 16250
-14300
and so on untill infinity so the answe ris 0.0254555555555555 (enless fives)
Answer and explanation:
Profit from sale of model boats = Sales -costs(costs of goods purchases + expenses or charges by the local fair)
John's profit from the sale of model boats can be represented by the equation:
P= 50x-(5x+80)
Where P is profit from the sale of the model boats and x is number of model boats bought and sold. The 80 is constant as it is a fixed cost paid to the local fair.
For example if John buys and sells 20 model boats, he would make profit of:
Substitute x=20 in equation above
P= 50×20-(5×20+80)
P=1000-180
P=$820
It could be said that John is in a very profitable business and his profit is also dependent on volume of sales because the lower his sales the closer he gets to making a loss and not profit
Click the answer button under there question
Answer:
Option C is correct...hope this helps:)
