Answer:
x= -11;y= -19
Step-by-step explanation:
lets name y-2x=3 "A" ;
name 3x-2y=5 "B".
2A: 2y-4x=6
2A+B: (2y-4x)+(3x-2y)=6+5
2y-4x+3x-2y=11
-x=11
so x= -11
so A is : y-2 (-11)=3
y+22=3
so
y= -19
Answer:
-16/65
Step-by-step explanation:
Given sinα = 3/5 in quadrant 1;
Since sinα = opp/hyp
opp = 3
hyp = 5
adj^2 = hyp^2 - opp^2
adj^2 = 5^2 = 3^2
adj^2 = 25-9
adj^2 = 16
adj = 4
Since all the trig identity are positive in Quadrant 1, hence;
cosα = adj/hyp = 4/5
Similarly, if tanβ = 5/12 in Quadrant III,
According to trig identity
tan theta = opp/adj
opp = 5
adj = 12
hyp^2 = opp^2+adj^2
hyp^2 = 5^2+12^2
hyp^2 = 25+144
hyp^2 = 169
hyp = 13
Since only tan is positive in Quadrant III, then;
sinβ = -5/13
cosβ = -12/13
Get the required expression;
sin(α - β) = sinαcosβ - cosαsinβ
Substitute the given values
sin(α - β) = 3/5(-12/13) - 4/5(-5/13)
sin(α - β)= -36/65 + 20/65
sin(α - β) = -16/65
Hence the value of sin(α - β) is -16/65
Answer:
Step-by-step explanation:
Given
The attached graph
Required
This is the point where
On the attached graph;
when
Hence:
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