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2 years ago

Pls help I don't understand what is x→7 x+2-3x-7

Mathematics

1 answer:

valkas [14]2 years ago

5 0

Answer:

Step-by-step explanation:

7x+2-3x-7 I believe this is impossible because ther will be no equal sign so please enter it again or?

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When testing a hypothesis about a single mean, a sample size of 200 is selected from a normally distributed population. If the p

Evgen [1.6K]

Answer:

Null hypothesis: $\mu \leq \mu_o$

Alternative hypothesis: $\mu > \mu_o$

If we analyze the size for the sample is > 30 and we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Step-by-step explanation:

Data given and notation

$\bar X$ represent the sample mean

$\sigma$ represent the population standard deviation for the sample

$n=200$ sample size

$\mu_o$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is equal to $\mu_o$ , the system of hypothesis would be:

Null hypothesis: $\mu \leq \mu_o$

Alternative hypothesis: $\mu > \mu_o$

If we analyze the size for the sample is > 30 and we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

5 0

4 years ago

PLEASE HELP IM DESPERATE precalculus. also 50 points!! please god help

kompoz [17]

Answer:

For B thru F these options will vary but here how you do it

B. Step 1 Draw the 4 Quadrants.

Then Draw the Triangle in the lower right quadrant which we call quadrant 4. Label the X axis as Adjacent and positive. Label the Y axis as Opposite and negative. Label the Slanted side as the hypotune and AS POSITVE SINCE HYPOTENUSE IS ALWAYS POSITIVE.

FOR C. IN QUADRANT 2, PLOT A POINT AT 0,12 AND AT (-5,0). CONNECT THE DOTS AND IT FORMS A TRIANGLE. Label the X axis as adjacent and negative and the y axis as positve and opposite and label the slanted side hypotunese and positive.

FOR D Draw a straight line along the x axis then draw a slanted line passing through (5,-1). In between them put the theta symbol in there.

The labeling is the same for C.

For E. Since tan must be positve and secant must be positve, our triangle must be in the 1st Quadrant. Draw any right triangle as long it is in the first quadrant

The x axis is adjacent and positve. The y axis is opposite and positve. The hypotenuse is the slanted side and it is positve.

For F. Since sin is negative and cos is positve the triangle is in the 4th quadrant. Draw any triangle in the 4th quadrant and the labeling is the same for Problem B.

2. We can find the sec of cos by flipping cosine.

$\cos( \frac{x}{y} ) = \sec( \frac{y}{x} )$

$\cos( \frac{1}{2} ) = \sec(2 )$

Sec is 2.

To find the cotangent, first let find the sin then tan.

We can use the identity

$\cos( {theta}^{2} ) + \sin( {theta}^{2} ) = 1$

Let plug in the number

$\cos( \frac{ {1}^{2} }{{2}^{2} } ) + \sin(x {}^{2} ) = 1$

$\cos( \frac{1}{4} ) + \sin(x {}^{2} ) = 1$

$\sin(x {}^{2} ) = 1 - \frac{1}{4}$

$\sin(x {}^{2} ) = \frac{3}{4}$

$\sin(x) = \frac{ \sqrt{3} }{ \sqrt{4} }$

$\sin(x) = \frac{ \sqrt{3} }{2}$

Since sin is negative, sin x=

$- \frac{ \sqrt{3} }{2}$

Now let apply the formula

$\frac{ \sin(x) }{ \cos(x) } = \tan(x)$

$\frac{ \frac{ - \sqrt{3} }{2} }{ \frac{1}{2} } = \tan(x)$

$- \sqrt{3}$

Now let find cotangent we can the reciprocal of

tan.

$\tan= - \sqrt{3}$

$\cot = - \frac{1}{ \sqrt{3} }$

Rationalize denominator

$\frac{ - 1}{ \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} } = \frac{ \sqrt -{ 3} }{3}$

cotangent equal

$- \frac{ \sqrt{ 3} }{3}$

4 0

3 years ago

What is the probability of rolling a 6 and then a 1 on consecutive rolls of a standard, 6-sided number cube?

ratelena [41]

Hello from MrBillDoesMath!

Answer:

1/36

Discussion:

The events of are unrelated ("mutually exclusive") so the probability of both happening is the product of the individual probabilities. That is,

(1/6) * (1/6) = 1/36

Thank you,

MrB

5 0

3 years ago

Read 2 more answers

A yogurt machine makes

Norma-Jean [14]

Step-by-step explanation:

the relationship between x and y is defined by a constant factor.

you can "go" from x to y and from y to x consistently and without any interruptions by applying that constant factor.

that makes it a linear relationship (a line on a chart, hence the name).

proportional relationships are relationships between two variables where their ratios are equivalent. another way to think about them is that, in a proportional relationship, one variable is always a constant value times the other. That constant is know as the "constant of proportionality".

so, yes, it is proportional.

and the table is then

x y

0 0

3 3×2/3 = 2

6 6×2/3 = 4

9 9×2/3 = 6

4 0

2 years ago

What are the values of x and y in the parallelogram?

postnew [5]

9514 1404 393

Answer:

x = 60

y = 30

Step-by-step explanation:

Adjacent angles are supplementary.

(5x -180) +x = 180

6x = 360 . . . . . . . . . . add 180, collect terms

x = 60 . . . . . . . . divide by 6

Opposite angles are congruent.

2y = 60 . . . . . . 2y = x

y = 30 . . . . . . . .divide by 2

The value of x is 60; the value of y is 30.

6 0

3 years ago