Pls help I don't understand what is x→7 x+2-3x-7
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Hey there :)
14) The perimeter of this square is given as 28a²b⁴
The perimeter formula of a square is P = 4 x side
28a²b⁴ = 4s
7a²b⁴ = s
Area formula of a square is:
A = side²
= ( 7a²b⁴)²
= 49a⁴b⁸
15)
Let's deal with it one by one and combine at the end
Numerator = ( r²st³ )( 20r⁻³s⁻¹t⁻⁴ )
The product of power rule applies here
= ( 20r⁻¹t⁻¹ ) → { r²⁺⁽⁻³⁾s¹⁻¹t³⁺⁽⁻⁴⁾ }
Denominator = ( -4r⁻²t )³
The power of a product rule applies here
= ( -64r⁻⁶t³ ) → ((-4)³(r⁻²ˣ³)(t)³)
Combine =
Quotient of powers rule apply here
Lets separate again:
, 
Final =
16)![\sqrt[3]{x^4}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx%5E4%7D%20)
The power inside the root will be the numerator and root number will be the denominator
17)
× 
The numerator will be the power inside and the denominator will be the root number
![\sqrt[8]{x^3}](https://tex.z-dn.net/?f=%20%5Csqrt%5B8%5D%7Bx%5E3%7D%20)
14) The perimeter of this square is given as 28a²b⁴
The perimeter formula of a square is P = 4 x side
28a²b⁴ = 4s
7a²b⁴ = s
Area formula of a square is:
A = side²
= ( 7a²b⁴)²
= 49a⁴b⁸
15)
Let's deal with it one by one and combine at the end
Numerator = ( r²st³ )( 20r⁻³s⁻¹t⁻⁴ )
The product of power rule applies here
= ( 20r⁻¹t⁻¹ ) → { r²⁺⁽⁻³⁾s¹⁻¹t³⁺⁽⁻⁴⁾ }
Denominator = ( -4r⁻²t )³
The power of a product rule applies here
= ( -64r⁻⁶t³ ) → ((-4)³(r⁻²ˣ³)(t)³)
Combine =
Quotient of powers rule apply here
Lets separate again:
Final =
16)
The power inside the root will be the numerator and root number will be the denominator
17)
The numerator will be the power inside and the denominator will be the root number