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CaHeK987 [17]
2 years ago
10

a designer created a scale drawing of a new kitchen. In the scale drawing, the length of the kitchen will be 8 feet. What scale

did the designer use to create the scale drawing of the kitchen
Mathematics
1 answer:
damaskus [11]2 years ago
3 0

Answer:

See Explanation

Step-by-step explanation:

Given

Scale\ length = 8ft

Required

Determine the scale of the drawing

<em>The question is incomplete, as the actual width of the kitchen is not given. The general explanation, however, is as follows:</em>

<em></em>

The scale of a drawing is represented as:

Scale = Scale\ Measurement : Actual\ Measurement

This gives:

Scale = 8ft : Actual

Assume the actual length of the kitchen is 24ft.

The equation becomes:

Scale = 8ft : 24ft

Divide by 8ft

Scale = 8ft/8ft : 24ft/8ft

Scale = 1 : 3

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Answer:

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Step-by-step explanation:

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Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest speed measured was 75.6 Mbp
olga55 [171]

Answer:

a) 59.98

b) 2.99

c) 2.99

d) Significantly High

Step-by-step explanation:

Part a)

Highest speed measured = x = 75.6 Mbps

Average/Mean speed = \overline{x} = 15.62 Mbps

Standard Deviation = s = 20.03 Mbps

We need to find the difference between carrier's highest data speed and the mean of all 50 data​ speeds i.e. x - \overline{x}

x - \overline{x} = 75.6 - 15.62 = 59.98 Mbps

Thus, the difference between​ carrier's highest data speed and the mean of all 50 data​ speeds is 59.98 Mbps

Part b)

In order to find how many standard deviations away is the difference found in previous part, we divide the difference by the value of standard deviation i.e.

\frac{59.98}{20.03}=2.99

This means, the difference is 2.99 standard deviations or in other words we can say, the Carrier's highest data speed is 2.99 standard deviations above the mean data speed.

Part c)

A z score tells us that how many standard deviations away is a value from the mean. We calculated the same in the previous part. Performing the same calculation in one step:

The formula for the z score is:

z=\frac{x-\overline{x}}{s}

Using the given values, we get:

z=\frac{75.6-15.62}{20.03}=2.99

Thus, the Carriers highest data is equivalent to a z score of 2.99

Part d)

The range of z scores which are neither significantly low nor significantly​ high is -2 to + 2. The z scores outside this range will be significant.

Since, the z score for carrier's highest data speed is 2.99 which is well outside the given range, i.e. greater than 2, we can conclude that the  carrier's highest data speed​ is significantly higher.

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