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madam [21]
3 years ago
13

What is the measure of 162 A. 324° B. 162° O C. 81° D. 72°

Mathematics
1 answer:
telo118 [61]3 years ago
4 0

Answer:

81

Step-by-step explanation:

trust me its correct

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A music teacher sells piano lesson packages. Piano Lesson Packages Total Cost Number of Lessons $90: 10 $160: 20 $80: 10 $120: 2
iragen [17]

Answer:

D. $120 for 20 lessons

Step-by-step explanation:

Based on the data provided we can decide which package is best by first calculating how much each package is charging per lesson. We do this by dividing the total dollar amount of each package by the number of lessons offered in that package. Then we simply compare each package to see which package charges the least amount for every single lesson like so...

$90 / 10 = $9 per lesson

$160 / 20 = $8 per lesson

$80 / 10 = $8 per lesson

$120 / 20 = $6 per lesson

Based on these values we can see that the cheapest package is $120 for 20 lessons which would be $6 per lesson.

5 0
3 years ago
Which expression has a greater value 1/2 × 345 + 791 or 345 + 791
nordsb [41]

Answer:

The expression 345+791 has a greater value.

Step-by-step explanation:

The first step to figuring out this problem would be to solve the following expressions: 1/2*345=172.5                345+791=1136

The next step to solving the problem would be to compare your answers from your solved expressions: 1136>172.5      OR        172.5<1136      

HOPE THIS HELPS BESTIEE

6 0
3 years ago
Vertex of the following quadratic function Y=3(x-5)^2+6
hoa [83]

Answer:

The vertex of the function is (5,6).

Step-by-step explanation:

The equation is already written in vertex form. Given a quadratic function with a vertex of (h,k), the equation for the graph is y=a(x-h)^2+k.

We can extract h and k from the provided equation and get the point (5,6)

7 0
3 years ago
Read 2 more answers
Ned walks 6 tenths of a mile to school.Fred walks 9 tenths of a mile to school.who walks farther?.Explain
FromTheMoon [43]
Fred. .9 is larger than .6 therefore, Fred walked a longer distance.
8 0
3 years ago
Read 2 more answers
A man 2 m high observes the angle of elevation to the top of a building to be 71° and the angle of depression to the bottom of t
Yuki888 [10]

Answer:

The building is 13.91 m tall

Step-by-step explanation:

The parameters given are;

Angle of elevation to the top of the building = 71°

Angle of depression to the bottom of the building = 26°

Height of the man = 2  m

Therefore, the sight of the man, the man's height, and the distance of the man from the building forms a triangle where:

The hypotenuse side = The sight of the man to the bottom of the building

Hence;

In ΔABC, A being at the eye level or head level of the man, B at the foot and C at the bottom of the building

∴ ∠A + Angle of depression to the bottom of the building = 90°

∠A = 90° - 26° = 64°

∠B = 90° and ∠C = 26° (Sum of angles in a triangle)

Tan(C) = \frac{AB}{BC}

Distance of the man from the building = BC

Tan(26) = \frac{2}{BC}

BC= \frac{2}{ Tan(26) } = 4.1 \, m

Given that the angle of elevation to the top of the building = 71°, we have;

ΔAET

Where:

A is at the head level of the man,

E is the point on the building directing facing the man and

T is the top of the building

Hence AE = BC and ∡TAE = 71°

TE + AB= The height of the building

Tan(TAE) = \dfrac{TE}{AE}\\\\Tan(71) = \dfrac{TE}{4.1}

∴ TE = tan(71°) × 4.1 = 11.91 m

Hence the height of the building = 11.91 + 2 = 13.91 m.

4 0
3 years ago
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