URGENT! The diagonal of a rectangle has length 15. If the base of the rectangle is 12, find the height.

Mathematics

1 answer:

AlekseyPX2 years ago

4 0

Answer: Height =9

Step-by-step explanation:

Given: The diagonal of a rectangle has length 15.

Base of the rectangle is 12.

Since each angle in a rectangle is 90°°.

Therefore , th triangle formed by joining diagonal with base and hight is a right triangle.

In right triangle , $Hypotenuse^2=Perpendicular ^2+base^2$ [Pythagoras theorem]

$\Rightarrow\ 15^2=heigt^2+12^2\\\\\Rightarrow\ height^2= 15^2-12^2\\\\\Rightarrow\ height^2= 225-144\\\\\Rightarrow\ height^2= 81\\\\\Rightarrow\ height=9$

Hence, the height =9

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In your computation, approximate its value as 3.14.

andrey2020 [161]

Answer: d

Step-by-step explanation:

Find the area of the rectangle.

$A=l*w\\A=(15in)(12in)\\A=180in^2$

Find the area of the base of the semicircle.

$A=\pi r^2$

12 in would be the diameter, divide by 2 to get the radius.

$\frac{12}{2}=6$

Plug this into the formula.

$A=(3.14)(6)^2\\A=113.04in^2$

Since we do not have a full circle but a semi one instead, we must divide our result by 2.

$\frac{113.04}{2}=56.52in^2$

Add both areas.

180+56.52=236.52 $in^2$

7 0

2 years ago

Write a general formula to describe the variation: M varies jointly with the cube root of the difference B and b.

MAXImum [283]

$\bf \qquad \qquad \textit{direct proportional variation}\\\\
\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad variation
\end{array}\\\\
-------------------------------\\\\
\stackrel{\textit{M varies jointly with the cube root of the difference B and b}}{M=k\sqrt[3]{B-b}}$