If the center is at (0, 0) and the vertex is at (20, 0), then the distance, a, is the length from the center to the vertex, 20. The distance from the center to the focus is c. The distance from the center to the focus is 16, so c = 16. The formula we use to find the focus is
. We have our c value and our a value, so we will sub in those to find b.
and 256 = 400 - b^2. -b^2 = -144, so b = 12. There you go!
it is true
Y=1/2 c + 1=81 so the answer is a-True
They can be different because Daryl is doing it online so he will not have to swing arcs on the computer screen he will just use circles. Hope that this helps!
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Answer:
The points for the given to linear equations is (5 , - 2) and (5 , - 1)
The points is plotted on the graph shown .
Step-by-step explanation:
Given as :
The two linear equation are
y = 
x - 1 ...........1
y = 
x - 6 ...........2
Now, Solving both the linear equations
Put the value of y from eq 2 into eq 1
I.e x - 6 = x - 1
Or, x + 
x = 6 - 1
Or, 
x = 5
or, 
x = 5
∴ x = 5
Now, Put the value of x in eq 1
So, y = x - 1
Or, y = × 5 - 1
or, y = 
- 1
Or, y = - 1 - 1
I.e y = -2
So, For x = 5 , y = - 2
Point is (
, 
) = (5 , - 2)
Again , put the value of x in eq 2
So, y = x - 6
Or, y = × 5 - 6
Or, y = 
- 6
Or, y = 4 - 6
I.e y = - 2
So, For x = 5 , y = - 2
Point is (
, 
) = (5 , - 2)
Hence, The points for the given to linear equations is (5 , - 2) and (5 , - 2)
The points is plotted on the graph shown . Answer
