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3 years ago

What is the area or the figure below?

Mathematics

2 answers:

Vedmedyk [2.9K]3 years ago

8 0

You have 2 shapes to find the area of Then add them together

The area of the rectangle is 5 x10= 50

The area of the triangle is 1/2b x h

1/2 x5 x 10=25

50+25=75

nataly862011 [7]3 years ago

5 0

U have to cross out the 10 then u have those 4 5s 5x5=25 5x5=25 25+25=50.

(My answer might be wrong so wait until other ppl answer. If I got riGhT like my thing -3-)

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Point p is on the terminal side

strojnjashka [21]

The value of the cotΘ will be 1.It is the ratio of the base and the perpendicular.

<h3>What is trigonometry?</h3>

The field of mathematics is concerned with the relationships between triangles' sides and angles, as well as the related functions of any angle.

The value of the cotΘ is found as;

$\rm cot \theta = \frac{B}{P} \\\\ \rm cot \theta = \frac{5}{5} \\\\ cot \theta = 1$

To learn more about trigonometry, refer to the link brainly.com/question/26719838

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2 years ago

You have $30 to spend on gas for your vehicle this week. If gas costs $2.42 per gallon, how many gallons of gas can you buy? Rou

BartSMP [9]

Answer:

you can get 12 gallons on gas

Step-by-step explanation:

x/30=1/2.42

step 1) cross multiply

x * 2.42 = 1 * 30

2.42x=30

step 2) divide both sides by 2.42

2.42x/2.42 = 30/2.42

= 12.396694

round to the nearest gallon

≈12 gallons

5 0

3 years ago

There is a large number of cubes in a bag.

Alla [95]

Marked(10)/total = 3/20 (from sample)

total/10 = 20/3 (inverting the above proportion)

total = 10•20/3 = 200/3 ≈ 67

7 0

3 years ago

Help please!!

IRINA_888 [86]

I think it’s QT EJ and HA

7 0

3 years ago

Read 2 more answers

PLEASE HELP! I'll give 5 out of 5 stars, give thanks, and give as many points as I can.

Liula [17]

Answer:

$\boxed{\boxed{x=\dfrac{\pi}{3}\ \vee\ x=\pi\ \vee\ x=\dfrac{5\pi}{3}}}$

Step-by-step explanation:

$\cos(3x)=-1\iff3x=\pi+2k\pi\qquad k\in\mathbb{Z}\\\\\text{divide both sides by 3}\\\\x=\dfrac{\pi}{3}+\dfrac{2k\pi}{3}\\\\x\in[0,\ 2\pi)$

$\text{for}\ k=0\to x=\dfrac{\pi}{3}+\dfrac{2(0)\pi}{3}=\dfrac{\pi}{3}+0=\boxed{\dfrac{\pi}{3}}\in[0,\ 2\pi)\\\\\text{for}\ k=1\to x=\dfrac{\pi}{3}+\dfrac{2(1)\pi}{3}=\dfrac{\pi}{3}+\dfrac{2\pi}{3}=\dfrac{3\pi}{3}=\boxed{\pi}\in[0,\ 2\pi)\\\\\text{for}\ k=2\to x=\dfrac{\pi}{3}+\dfrac{2(2)\pi}{3}=\dfrac{\pi}{3}+\dfrac{4\pi}{3}=\boxed{\dfrac{5\pi}{3}}\in[0,\ 2\pi)\\\\\text{for}\ k=3\to x=\dfrac{\pi}{3}+\dfrac{2(3)\pi}{3}=\dfrac{\pi}{3}+\dfrac{6\pi}{3}=\dfrac{7\pi}{3}\notin[0,\ 2\po)$

7 0

3 years ago

Read 2 more answers