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3 years ago

10

Sergio went to the library at 3:18 p.m. to do homework. He worked at the library for 57 minutes, then left to go home. What time

did Sergio leave the library?

1 answer:

8_murik_8 [283]3 years ago

6 0

Answer:

The time would be 4:15 I think

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An architect draws a blueprint of a house. He draws the living room on the blueprint as 4.5 in. long by 6 in. wide with a scale

s2008m [1.1K]

Answer:

the answer is 8.5

Step-by-step explanation:

yeet

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3 years ago

Read 2 more answers

Pls help me .question no 14

Alex_Xolod [135]

Question 14, Part (i)

Focus on quadrilateral ABCD. The interior angles add to 360 (this is true for any quadrilateral), so,

A+B+C+D = 360

A+90+C+90 = 360

A+C+180 = 360

A+C = 360-180

A+C = 180

Since angles A and C add to 180, this shows they are supplementary. This is the same as saying angles 2 and 3 are supplementary.

==================================================

Question 14, Part (ii)

Let

x = measure of angle 1

y = measure of angle 2

z = measure of angle 3

Back in part (i) above, we showed that y + z = 180

Note that angles 1 and 2 are adjacent to form a straight line, so we can say

x+y = 180

-------

We have the two equations x+y = 180 and y+z = 180 to form this system of equations

$\begin{cases}x+y = 180\\y+z = 180\end{cases}$

Which is really the same as this system

$\begin{cases}x+y+0 = 180\\0+y+z = 180\end{cases}$

The 0s help align the y terms up. Subtracting straight down leads to the equation x-z = 0 and we can solve to get x = z. Therefore showing that angle 1 and angle 3 are congruent. We could also use the substitution rule to end up with x = z as well.

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3 years ago

The Rivertown city council is attempting to choose one of four sites (A, B, C, or D) as the location for its new emergency facil

Vikki [24]

Answer:

SITE A

Step-by-step explanation:

Given :

proposed-site Area-Served

1 2 3 4

A 5.2 4.4 3.6 6.5

B 6.0 7.4 3.4 4.0

C 5.8 5.9 5.9 5.8

D 4.3 4.8 6.5 5.1

Area 1 2 3 4

Number-runs 150 65 175 92

Computing the weighted average for the 4 sites :

Site A:

((150*5.2) + (65*4.4) + (175*3.6) + (92*6.5)) / (150 + 65 + 175 + 92)

= 2294 / 482

= 4.7593

Site B:

((150*6.0) + (65*7.4) + (175*3.4) + (92*4.0)) / (150 + 65 + 175 + 92)

= 2344/ 482

= 4.863

Site C:

((150*5.8) + (65*5.9) + (175*5.9) + (92*5.8)) / (150 + 65 + 175 + 92)

= 2819.6/ 482

= 5.850

Site D:

((150*4.3) + (65*4.8) + (175*6.5) + (92*5.1)) / (150 + 65 + 175 + 92)

= 2563.7/ 482

= 5.319

From the weighted average response time computed for the different sites ;

The best location for the emergency facility would be one with the least average response time; which is SITE A.

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3 years ago

Which questions best describes: A tire manufacturer has a 60,000 mile warranty for tread life. The manufacturer considers the ov

seropon [69]

This question is incomplete because the answer choices were not provided. The complete question was obtained from google as:

A tire manufacturer has a 60,000 mile warranty for tread life. The manufacturer considers the overall tire quality to be acceptable if less than 5% are worn out at 60,000 miles. The manufacturer tests 250 tires that have been used for 60,000 miles. They find that 3.6% of them are worn out. With this data, we test the following hypotheses.

H0: The proportion of tires that are worn out after 60,000 miles is equal to 0.05.

Ha: The proportion of tires that are worn out after 60,000 miles is less than 0.05.

In order to assess the evidence, which question best describes what we need to determine?

a. If we examine a sample of tires used for 60,000 miles and determine the proportion that are worn out, how likely is that proportion to be 3.6% or less?

b. If we examine the proportion of worn out tires in the population of tires used for 60,000 miles, how likely is that proportion to be 5%?

c. If we examine the proportion of worn out tires in the population of tires used for 60,000 miles, how likely is that proportion to be less than 5%?

d. If we examine the proportion of worn out tires in the population of tires used for 60,000 miles, how likely is that proportion to be 3.6%?

e. If we examine a sample of tires used for 60,000 miles and determine the proportion that are worn out, how likely is that proportion to be less than 5%?

Answer:

Option A is the correct question - If we examine a sample of tires used for 60,000 miles and determine the proportion that is worn out, how likely is that proportion to be 3.6% or less?

Step-by-step explanation:

The correct question that describes what needs to be determined is expressed in option A as this will give us p-value and we will guide us in deciding whether to keep or reject the null hypothesis

Thus option A is the correct question - If we examine a sample of tires used for 60,000 miles and determine the proportion that is worn out, how likely is that proportion to be 3.6% or less?

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3 years ago

What's the slope of (2,4) and (5,2) ??

bogdanovich [222]

-2/3
first do y2-y1 over x1-x2
then it’ll be 2-4 over 5-2
coming out as -2/3

4 0

3 years ago