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frutty [35]
3 years ago
8

Can someone helpppp plssss

Mathematics
2 answers:
Leokris [45]3 years ago
7 0

Answer:

angleQ+angleR is 180degrees because of the properties of isoceles trapezoid. So, if you set equation and solve, you'll get the fact that x is 12, and angleR is 130degrees, and angleQ is 50degrees. According to the properties of isoceles trapezoid, angleQ is the same as angleT. So, angleT is 50degrees

Veseljchak [2.6K]3 years ago
4 0

Answer:

Step-by-step explanation:

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Hhhhhhhhhhjhhjhhjhjjjjjjhhhhhhhhhh
marta [7]

Answer:

i know right? It's so difficult till I'm brainless when I try to solving it

8 0
3 years ago
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3 orange picks for every 2 green. if there are 25 picks in all, how many picks are orange?
Marta_Voda [28]
3+2=5
25÷5=5
5×3=15
There are 15 Orange picks.
8 0
3 years ago
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One year Roger had the lowest ERA​ (earned-run average, mean number of runs yielded per nine innings​ pitched) of any male p
baherus [9]

Answer:

(a) The <em>z</em>-score of Roger is -1.56 and the <em>z</em>-score of Amber is -1.13.

(b) Roger had a better year relative to his peers.

Step-by-step explanation:

If X follows N (<em>µ, σ</em>₂), then z=\frac{x-\mu}{\sigma}, is a standard normal variate with mean,      E (Z) = 0 and Var (Z) = 1. That is, Z follows N (0, 1).

Let <em>X</em> = ERA of male pitchers and <em>Y</em> = ERA of ERA of female pitchers.

It is provided that the mean and standard deviation of <em>X</em> are:

\mu_{X}=4.371\\\sigma_{X}=0.787

Also, the mean and standard deviation of <em>Y</em> are:

\mu_{Y}=4.363\\\sigma_{Y}=0.869

ER of Roger is 3.14 and ERA of Amber is 3.38.

(1)

Compute the <em>z</em>-score of Roger as follows:

z=\frac{x-\mu_{X}}{\sigma_{X}}=\frac{3.14-4.371}{0.787}=-1.56

Thus, the <em>z</em>-score of Roger is -1.56.

Compute the <em>z</em>-score of Amber as follows:

z=\frac{x-\mu_{Y}}{\sigma_{Y}}=\frac{3.38-4.363}{0.869}=-1.13

Thus, the <em>z</em>-score of Amber is -1.13.

(2)

Compute the probability of ERA's that are greater than Roger's ERA as follows:

P(X>3.14)=P(\frac{X-\mu}{\sigma}>\frac{3.14-4.371}{0.787})\\=P(Z>-1.56)\\=P(Z

This implies that 94% of the other male pitchers had an ERA higher than 3.14.

Compute the probability of ERA's that are greater than Amber's ERA as follows:

P(Y>3.38)=P(\frac{Y-\mu_{Y}}{\sigma_{Y}}>\frac{3.38-4.363}{0.869})\\=P(Z>-1.13)\\=P(Z

This implies that 87% of the other female pitchers had an ERA higher than 3.38.

As it is provided that the lower the ERA the better the pitcher, then it can be concluded that Roger had a better year relative to his peers.

4 0
4 years ago
To find the roots of the function, set y = 0. The equation is 0 = 4x2 + 2x – 30.
Assoli18 [71]

Answer:

x = - 3, x = \frac{5}{2}

Step-by-step explanation:

Given

4x² + 2x - 30 = 0 ( divide through by 2 )

2x² + x - 15 = 0

Consider the factors of the product of the x² term and the constant term which sum to give the coefficient of the x- term.

product = 2 × - 15 = - 30 and sum = + 1

The factors are + 6 and - 5

Use these factors to split the x- term

2x² + 6x - 5x - 15 = 0 ( factor the first/second and third/fourth terms )

2x(x + 3) - 5(x + 3) = 0 ← factor out (x + 3) from each term

(x + 3)(2x - 5) = 0

Equate each factor to zero and solve for x

x + 3 = 0 ⇒ x = - 3

2x - 5 = 0 ⇒ 2x = 5 ⇒ x = \frac{5}{2}

4 0
4 years ago
What is the value of n? 133, 142, n
Umnica [9.8K]
I assume that this is a sequence and you need to find the next number in the sequence.

The first two numbers are give as 133 and 142, we can get the difference between them by subtraction as follows:
142 - 133 = 9
This means that adding 9 will generate the next term as follows:
133
133+9 = 142
142 + 9 = 151
This means that : n=151
3 0
3 years ago
Read 2 more answers
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