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adell [148]
3 years ago
11

6. Sketch the region enclosed by the graphs of x =0, 6y-5x=0 and x+3y=21. Find the area

Mathematics
2 answers:
umka2103 [35]3 years ago
6 0

<span>Given three equations, x=0</span>

<span>6y-5x=0</span>

<span>x+3y=21</span>

<span>
</span>

<span>The lines cross at:</span>

<span>x=0, y=0</span>

<span>x=0, y=7</span>

<span>x=6, y=5</span>

<span>so base of triangle is the y-axis between 0 and 7</span>

<span>height is x=6</span>

<span>area=6*7/2=20.5</span>

<span>
</span>

<span>volume=1/3*(base area)*height</span>

<span>=1/3*(pi*6^2)*7</span>

<span>=84pi</span>

<span>=263.9</span>


Lyrx [107]3 years ago
5 0
X = 0

<span>6y - 5x = 0 so it intersects x=0 at (0,0)
</span>
<span>x + 3y = 21
</span>so it intersect x=0 at (0,7)
multiply by 2
<span>2x + 6y = 42
subtracting 6y - 5x = 0
7x = 42
x = 6
so the third line intersects w second line at (6,5)

6. area of triangle = 1/2*base*height
= 1/2*7*6
=21

7. volume = volume of 2 cones
cone volume = 1/3*pi*radius^2*height
lower cone: radius=6, height=5
upper cone: radius=6, height=7-5=2
volume = 1/3*pi*6^2*(5+2)
=84pi
=263.89

</span>
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Step-by-step explanation:

Step 1:

AC + BC = AB       Equation

Step 2:

18 + 7 = AB     Substitute

Answer:

25     Add

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Answer:

1. (4a+3)(4a-3)

2. (2m + 5)(2m-5)

3. (4b-5)²

4. (2x-1)²

5. (3x+1)(3x-1)

6. (n+5)(n-5)

7. (n²-10)²

8. (a²+3)(a²-3)

9. (k²+6)(k²-6)

10. (n²+7)(n²-7)

Step-by-step explanation:

For special products like these, just remember the

Difference of Squares formula:

a^2 -b^2 = (a+b)(a-b)

and

Square of difference formula:

a^2-2ab+b^2=(a-b)²

1. 16a²-9 follows the difference of squares form:

a² - b² = (a+b)(a-b)

So all we need to do is get the square root of a and b and follow the form:

(√16a²) - (√9) = (4a +3) (4a - 3)

Let's check through FOIL:

(4a +3) (4a - 3)

16a² - 12a + 12a - 9

16a² - 9

2. 4m² - 25 also follows the same form of difference of squares:

(√4m²) - (√25) = (2m +5) (2m - 5)

Let's check!

(2m +5) (2m - 5)

4m² + 10m - 10m -25

4m² - 25

3. 16b² - 40b + 25 follows the form of square of difference:

a² - 2ab + b² = (a - b)²

√16b² = 4b

√25 = 5

(4b - 5)²

Let's check!

(4b-5)(4b - 5)

16b² - 20b - 20b + 25

16b² - 40b + 25

HEre's another way to look at it:

First multiply the coefficients of the first and last term:

16 x 25 = 400

Next think of two numbers that when you multiply them, you will come up with 400 and sum up to -40. The two numbers would be -20 and -20 which will be the middle term

So it would fill in this way:

16b² - 20b - 20b + 25

Factor the equation:

(16b² - 20b) (-20b + 25)

4b(4b-5) - 5(4b-5)

(4b-5)(4b-5) = (4b-5)²

4. 4x² - 4x + 1 follows that same form:

√4x² = 2x

√1 = 1

(2x - 1)²

Let's check!

(2x - 1)(2x - 1)

4x² - 2x - 2x + 1

4x²- 4x + 1

5. 9x² - 1 follows the form of difference of squares:

√9x² - √1 = (3x + 1)(3x - 1)

Let's check!

(3x + 1)(3x - 1)

9x² + 3x - 3x - 1

9x² - 1

6. n² - 25 follows the form of difference of squares:

√n² - √25 = (n + 5)(n - 5)

Let's check!

(n + 5)(n - 5)

n² + 5n - 5n - 25

n² - 25

7. n⁴ - 100

√n⁴ - √100 = (n² + 10)(n² - 100)

Let's check!

(n² + 10)(n² - 100)

n⁴ + 10n² - 10n² -100

n⁴ - 100

8. a⁴ - 9

√a⁴ - √9 = (a² + 3)(a² - 3)

Let's check!

(a² + 3)(a² - 3)

a⁴ + 3a² - 3a² - 9

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9. k⁴ - 36

√k⁴ - √36 = (k² + 6) (k² - 6)

Let's check!

(k² + 6) (k² - 6)

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10. n⁴ - 49

√n⁴ - √49 = (n² + 7) (n² - 7)

Let's check!

(n² + 7) (n² - 7)

n⁴ +7n² - 7n²- 49

n⁴ - 49

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