Answer:
Number of positive four-digit integers which are multiples of 5 and less than 4,000 = 600
Explanation:
Lowest four digit positive integer = 1000
Highest four digit positive integer less than 4000 = 3999
We know that multiples of 5 end with 0 or 5 in their last digit.
So, lowest four digit positive integer which is a multiple of 5 = 1000
Highest four digit positive integer less than 4000 which is a multiple of 5 = 3995.
So, the numbers goes like,
1000, 1005, 1010 .....................................................3990, 3995
These numbers are in arithmetic progression, so we have first term = 1000 and common difference = 5 and nth term(An) = 3995, we need to find n.
An = a + (n-1)d
3995 = 1000 + (n-1)x 5
(n-1) x 5 = 2995
(n-1) = 599
n = 600
So, number of positive four-digit integers which are multiples of 5 and less than 4,000 = 600
Hello, Katrina7!
Vertical angles are when two lines intersect they form two pairs of opposite angles.
I really hope this helps;)
Answer:
The property used is the commutative property.
Step-by-step explanation:
In the commutative property, the sum is the same if you reorder the numbers.
I hope this helped! :-)
Answer: 14
<u>Step-by-step explanation:</u>
f(x) = 3x + 2
To find f⁻¹, swap the x's and y's and solve for y --> Note: f(x) is y
x = 3y + 2
x - 2 = 3y
f(f⁻¹(14)) = f(4)
f(4) = 3(4) + 2
= 12 + 2
= 14
NOTE: the simplified version is .... f and f⁻¹ cancel out, leaving you with 14
If you have snap you can use that just hold down on screen your problem
