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Oksi-84 [34.3K]
3 years ago
5

A uniform bar of length l and weight w is attached to a wall with a hinge that exerts a horizontal force hx and a vertical force

hy on the bar. the bar (which makes an angle θ with respect to wall) is held by a cord that makes a 90◦ angle with respect to bar. what is the magnitude of the tension t in the cord?
Mathematics
1 answer:
maria [59]3 years ago
4 0
The answer is Hx = ½ Wsin θ cos θ
The explanation for this is:
Analyzing the torques on the bar, with the hinge at the axis of rotation, the formula would be: ∑T = LT – (L/2 sin θ) W = 0
So, T = 1/2 W sin θ. Analyzing the force on the bar, we have: ∑fx = Hx – T cos θ = 0Then put T into the equation, we get:∑T = LT – (L/2 sin θ) W = 0
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3 years ago
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Rina8888 [55]

The two column proof for the given angle addition has been carried out below.

<h3>How to Carry out two column proof?</h3>

1) m∠CZE = m∠1 + m∠2

Reason: Angle Addition Property

2) m∠FXH = m∠3 + m∠4

Reason: Angle Addition Property

3) m∠CZE = m∠FXH

Reason: Given

4) m∠1 + m∠2 = m∠3 + m∠4

Reason: Substitution Property

5) m∠1 = m∠3

Reason: Subtraction Property

6) m∠3 + m∠2 = m∠3 + m∠4

Reason: Substitution Property

7) m∠2 = m∠4

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Read more about Two Column Proof at; brainly.com/question/1788884

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3 years ago
Read 2 more answers
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