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Oksi-84 [34.3K]
3 years ago
5

A uniform bar of length l and weight w is attached to a wall with a hinge that exerts a horizontal force hx and a vertical force

hy on the bar. the bar (which makes an angle θ with respect to wall) is held by a cord that makes a 90◦ angle with respect to bar. what is the magnitude of the tension t in the cord?
Mathematics
1 answer:
maria [59]3 years ago
4 0
The answer is Hx = ½ Wsin θ cos θ
The explanation for this is:
Analyzing the torques on the bar, with the hinge at the axis of rotation, the formula would be: ∑T = LT – (L/2 sin θ) W = 0
So, T = 1/2 W sin θ. Analyzing the force on the bar, we have: ∑fx = Hx – T cos θ = 0Then put T into the equation, we get:∑T = LT – (L/2 sin θ) W = 0
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.<br> Evaluate ƒ(x) = 3x + 8 for x = 1.<br><br><br> 3<br><br><br> 5<br><br><br> 11<br><br><br> –11
rodikova [14]

Answer:

11

Step-by-step explanation:

Replace the variable xx with −1-1 in the expression.

f(−1)=−3⋅−1+8f(-1)=-3⋅-1+8

Simplify the result.

Tap for fewer steps...

Multiply −3-3 by −1-1.

f(−1)=3+8f(-1)=3+8

Add 33 and 88.

f(−1)=11f(-1)=11

The final answer is 1111.

=11

I want brainless pleased

8 0
2 years ago
the empire state building is 1250 feet tall. IF an object is thrown upward from the top of the building at an initial velocity o
ss7ja [257]

Answer:

Time for the object to get h(max)    s = 1.1875 sec

h (max)  = 1272.57 feet

Down time for the object to hit the ground   =  4.25 sec

Step-by-step explanation:

The relation

h(s)  =  -  16*s²  +  38* s  + 1250    (1)

Is equivalent to the equation for vertical shot

Δh = V(i)*t  -  1/2g*t²  (in this case we don´t have independent term since the shot is from ground level. We can see in (1), the independent term is 1250 feet ( the height of the empire state building), the starting point of the movement.

The description of the movement is:

V(s)  =  V(i)  - g*s     ⇒  V(s) = 38 - 32*s

At h(max)    V(s)  =  0      38/32  = s

So the maximum height is at  s = t = 1.1875 sec

The time for the object to pass for starting point is the same

t  =  1.1875 sec

h(max) is

h(max)  = - 16* (1.1875)² +  38 (1.1875) + 1250

h(max)  =  -  22,56  +  45.13  +  1250

h(max)  =  1272.57 feet

Time for the object to hit the ground is

h(s)  =  - 1250 feet

-1250  =  - 16 s² + 38*s  + 1250

-16s² +  38s  =  0

s ( -16s + 38 )  =  0

First solution for that second degree equation  is x = 0 which we dismiss

then  

( -16s + 38 )  =  0    ⇒ 16s   =  38     s  =  38/16

s =  2.375 sec    and  we have to add time between h (max) and to get to starting point  ( 1. 1875 sec)

total time is  = 2.375 + 1.875

Total time  =  4.25 sec

4 0
3 years ago
The increase in a person’s body temperature T(t), above 98.6ºF, can be modeled by the function T(t)=4t/t^2+1, where trepresents
elena-14-01-66 [18.8K]
The meaning of the horizontal asymptote is that the increase in a person's body temperature is a constant value when long time passes.

You can obtain that value by calculating the limit of the function when t → ∞:

                 4t
T(t) =  ------------- => Lim T(t) when t → +∞ = 0.
             t^2 + 1

That means that at long term the Temperature tends to remain at 98.6°F.
7 0
2 years ago
Cans of regular soda have volumes with a mean of 13.3813.38 oz and a standard deviation of 0.110.11 oz. is it unusual for a can
dimulka [17.4K]
No 13.3813 + 0.1100 = 13.4913. (max. standard deviation)
13.4813 is less than max. standard deviation
8 0
3 years ago
Am I correct? If so why?
babunello [35]

Answer: its correct

Step-by-step explanation: and its correct cuase its the answer you choose

7 0
2 years ago
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