All categories

2 years ago

Denise has taken four math tests this semester and

Mathematics

1 answer:

Viefleur [7K]2 years ago

4 0

Answer:

Step-by-step explanation:

Setup an equation. Add the 5 tests together, the unknown test will be represented by x, Since there are 5 tests total, you will divide by 5. to find the average.

$\frac{89 + 85+96+87+x}{5} = 90$

To solve first multiply both side by 5.

$(5) \frac{89 + 85+96+87+x}{5} = 90 (5)$

$89 + 85+96+87+x = 450$

Add the left side and then solve for x

$357 + x = 450$

Subtract 357 from both sides

357 - 357 + x = 450 - 357

x = 93

The last test has to be a score of 93 to get an average of 90.

You might be interested in

At noon on tuesday in Chicago the temperature in degrees Fahrenheit was -2 Fahrenheit at noon on Wednesday the temperature was 8

bagirrra123 [75]

The temperature was 6 degrees Fahrenheit

4 0

3 years ago

Read 2 more answers

Which point best represents V26 on the number line below?

LiRa [457]

Answer:

Th answer is C u got it right

Step-by-step explanation:

7 0

3 years ago

There are many cylinders with a height of 9 inches. Let r represent the

bazaltina [42]

Answer: 1- 9

2-36

3-81

Step-by-step explanation:

4 0

2 years ago

What is the length of the arc if: 11. r=10 n=20 A15(pi)/ 7 B13(pi)/ 5 C16(pi)/ 2 D11(pi)/ 4 E 10(pi)/ 9 F 9(pi)/ 4 12. r=3 n=6 A

Vilka [71]

Step-by-step explanation:

The formula for arc length [for the angle in degrees] is:

$L = 2\pi r \left(\dfrac{n}{360}\right)$

here,

$n$ = degrees

$r$ = radius

using this we'll solve all the parts:

r = 10, n = 20:

$L = 2\pi r \left(\dfrac{n}{360}\right)$

$L = 2\pi (10) \left(\dfrac{20}{360}\right)$

from here, it is just simplification:

2 and 360 can be resolved: 360 divided by 2 = 180

$L = \pi (10) \left(\dfrac{20}{180}\right)$

10 and 180 can be resolved: 180 divided by 10 = 18

$L = \pi \left(\dfrac{20}{18}\right)$

finally, both 20 and 18 are multiples of 2 and can be resolved:

$L = \pi \left(\dfrac{10}{9}\right)$

$L = \dfrac{10\pi}{9}$ Option (E)

r=3, n=6:

$L = 2\pi r \left(\dfrac{n}{360}\right)$

$L = 2\pi (3) \left(\dfrac{6}{360}\right)$

$L = \dfrac{\pi}{10}$ Option (D)

r=4 n=7

$L = 2\pi r \left(\dfrac{n}{360}\right)$

$L = 2\pi (4) \left(\dfrac{7}{360}\right)$

$L = \dfrac{7\pi}{45}$ Option (C)

r=2 n=x

$L = 2\pi r \left(\dfrac{n}{360}\right)$

$L = 2\pi (2) \left(\dfrac{x}{360}\right)$

$L = \dfrac{x\pi}{90}$ Option (D)

r=y n=x

$L = 2\pi r \left(\dfrac{n}{360}\right)$

$L = 2\pi (y) \left(\dfrac{x}{360}\right)$

$L = \dfrac{xy\pi}{180}$ Option (E)

6 0

3 years ago

Sarfcae area is the _______ of all the _____________of the faces of a three diamentsilal figure.

Leya [2.2K]

Answer:

The sum of the areas of all the surfaces (faces) of a three-dimensional figure.

Step-by-step explanation:

3 0

2 years ago