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3 years ago

8

Is the following relation a function? {(1,2), (3,4),(-2,4),(3,0)}

2 answers:

Nana76 [90]3 years ago

8 0

Answer:

Step-by-step explanation:

KengaRu [80]3 years ago

3 0

Answer:

yes

Step-by-step explanation:

a function has one uniqe output to a input

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Which of the following points is in the solution set of y < x2 - 2x - 8?<br>(-2, -1)(0, -2)(4, 0)

ratelena [41]

Y < (x - 4)(x + 2)

so the critical points are -2 and 4
(-2,-1) will be in the solution

( 0,-2) will not

(4,0) will not.
the answer is ((-2,-1)

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3 years ago

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If y varies inversely as x and y=24 when x=8, find y when x is 4

olga2289 [7]

Y would equal 12 if x were to equal 4. You can think of it as a proportion.

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3 years ago

Probabilities with possible states of nature: s1, s2, and s3. Suppose that you are given a decision situation with three possibl

amm1812

Answer:

1. $P(s_1|I)=\frac{1}{11}$

2. $P(s_2|I)=\frac{8}{11}$

3. $P(s_3|I)=\frac{2}{11}$

Step-by-step explanation:

Given information:

$P(s_1)=0.1, P(s_2)=0.6, P(s_3)=0.3$

$P(I|s_1)=0.15,P(I|s_2)=0.2,P(I|s_3)=0.1$

(1)

We need to find the value of P(s₁|I).

$P(s_1|I)=\frac{P(I|s_1)P(s_1)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_1|I)=\frac{(0.15)(0.1)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_1|I)=\frac{0.015}{0.015+0.12+0.03}$

$P(s_1|I)=\frac{0.015}{0.165}$

$P(s_1|I)=\frac{1}{11}$

Therefore the value of P(s₁|I) is $\frac{1}{11}$ .

(2)

We need to find the value of P(s₂|I).

$P(s_2|I)=\frac{P(I|s_2)P(s_2)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_2|I)=\frac{(0.2)(0.6)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_2|I)=\frac{0.12}{0.015+0.12+0.03}$

$P(s_2|I)=\frac{0.12}{0.165}$

$P(s_2|I)=\frac{8}{11}$

Therefore the value of P(s₂|I) is $\frac{8}{11}$ .

(3)

We need to find the value of P(s₃|I).

$P(s_3|I)=\frac{P(I|s_3)P(s_3)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_3|I)=\frac{(0.1)(0.3)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_3|I)=\frac{0.03}{0.015+0.12+0.03}$

$P(s_3|I)=\frac{0.03}{0.165}$

$P(s_3|I)=\frac{2}{11}$

Therefore the value of P(s₃|I) is $\frac{2}{11}$ .

4 0

3 years ago

A bag holds 1 blue block and 3 yellow blocks. How many green blocks should be added to the bag to make the probability of random

Drupady [299]

$n$ - the number of green blocks which is equal to the number of favourable events
$1+3+n=4n$ - the number of all blocks, which is equal to the number of all possible outcomes

$P(A)=\dfrac{n}{4+n}=\dfrac{1}{2}\\
1\cdot( 4+n)=2\cdot n\\
4+n=2n\\
2n-n=4\\
n=4
$

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Graph the number on the number line.

My name is Ann [436]

Answer:

Step-by-step explanation:

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