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mel-nik [20]
3 years ago
14

IF TWO ANGLES ARE CONSECUTIVE EXTERIOR ANGLES AND <1=59, WHAT IS THE MEASURE OF <2?

Mathematics
1 answer:
lutik1710 [3]3 years ago
6 0

Answer:

<2 = 121

Step-by-step explanation:

Consecutive exterior angles add up to 180 degrees.

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R varies directly as S and inversely as T. if R = 8 when S = 4 and T = 3, then R is equal to ​
Alex

Answer:

R = 6S/T

Step-by-step explanation:

R ∝ S/ T

》R = kS/ T

》k = RT/ S

If R = 8 when S = 4 and T = 3

then, k = (8 × 3)/ 4

k = 6

∴ R = (6 × S)/ T

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What is the product of 4 Over 5 times two-fifths?
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A ski lift is designed with a total load limit of 20,000 pounds. It claims a capacity of 100 persons. An expert in ski lifts thi
Yanka [14]

Answer:

0.5 = 50% probability that a random sample of 100 independent persons will cause an overload

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For the sum of n values of a distribution, the mean is \mu \times n and the standard deviation is \sigma\sqrt{n}

An expert in ski lifts thinks that the weights of individuals using the lift have expected weight of 200 pounds and standard deviation of 30 pounds. 100 individuals.

This means that \mu = 200*100 = 20000, \sigma = 30\sqrt{100} = 300

If the expert is right, what is the probability that a random sample of 100 independent persons will cause an overload

Total load of more than 20,000 pounds, which is 1 subtracted by the pvalue of Z when X = 20000. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{20000 - 20000}{300}

Z = 0

Z = 0 has a pvalue of 0.5

1 - 0.5 = 0.5

0.5 = 50% probability that a random sample of 100 independent persons will cause an overload

5 0
3 years ago
What are narcissistic numbers
konstantin123 [22]
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3 years ago
to advertise o radio,the radio station charges 32naira for the first 10 words and 2naira per word for every additional word.how
o-na [289]

Answer:

Cost for 68 words = 148 naira

Step-by-step explanation:

Given that:

Cost of first ten words = 32 naira

Cost of additional words = 2 naira per word

Let,

x be the number of additional words.

y be the total cost

y = 2x + 32

We have to find the cost for 68 words.

The cost of first 10 words will be 32 naira.

Additional words = 68 - 10 = 58 words

Putting x = 58 in the equation

y = 2(58) + 32

y = 116 + 32

y = 148

Hence,

Cost for 68 words = 148 naira

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2 years ago
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