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Nuetrik [128]
3 years ago
15

What are the roots of the polynomial equation? x2+11x−80=0

Mathematics
2 answers:
dolphi86 [110]3 years ago
5 0
The roots would be x=5,16
tino4ka555 [31]3 years ago
5 0

Answer: The roots of the polynomial equation are 5 and -16.

Step-by-step explanation:

Since we have given that

x^2+11x-80=0

So, we need to find the roots of the polynomial equation:

We will use "Split the middle term":

x^2+11x-80=0\\\\x^2+16x-5x-80=0\\\\x(x+16)-5(x-16)=0\\\\(x-5)(x+16)=0\\\\x=5,-16

Hence, the roots of the polynomial equation are 5 and -16.

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If u make 120.45 in 15 2/3 hours how long did u work if u made 40.15 ?
Novosadov [1.4K]

Answer:

about 5.22hrs

Step-by-step explanation:

cross multiply

<u>120.45</u>          <u>?</u>

15.67         40.15

120.45*40.15

=629.1505

629.1505/15.67

=5.2233333...

5 0
3 years ago
4x + 8 = 32 pleas eexplain
Sedbober [7]

Answer:

x = 6

Step-by-step explanation:

  • Subtract  8 from both sides of the equation
  • Simplify
  • Subtract the numbers
  • Divide both sides of the equation by the same term
  • Simplify
  • Cancel terms that are in both the numerator and denominator
  • Divide the numbers
  •  =  6
5 0
3 years ago
Read 2 more answers
Write the prime factorization of 3.
DaniilM [7]

Answer:

there is none prime factorization of 3. Since it cant be multiplied by anything to get 3 like 2 and 5 and 7

Step-by-step explanation:

5 0
3 years ago
susan mountain elevation is 1530 meters. After 4 hours of climbing down to her elvationis 680 meters. What is susans avarge chan
RideAnS [48]
2,650 meters per hour
8 0
2 years ago
Find the number of ways of arranging the numbers
Doss [256]

First of all, note that all integers are either 0,1, or 2 modulo 3 (if you're not familiar with this terminology, it means that every integer is either a multiple of 3, or it is 1 or 2 away from a multiple of 3).

So, we can think of our numbers as

\begin{array}{c|c}x&x\mod 3\\0&0\\1&1\\2&2\\3&0\\4&1\\5&2\\6&0\\7&1\\8&2\\9&0\end{array}

In order to make sure that the sum of any three adjacent numbers is divisible by 3, we have to make sure that any group of 3 three adjacent numbers contains a 0, a 1 and a 2. This is possible only if we arrange our 9 numbers in 3 groups of 3 numbers containing 0,1 and 2 exactly once, repeating always the same pattern.

For example, we could arrange our numbers following the pattern

0,1,2,0,1,2,0,1,2

or

2,0,1,2,0,1,2,0,1

We have 3!=6 possible patterns. Suppose for example that we choose the pattern

0,1,2,0,1,2,0,1,2

One possible way of following this pattern would be the arrangement

3,1,2,6,4,5,9,7,8

In fact, we substituted every '0' with a multiple of 3 (3, 6 or 9), every '1' with a number 1 away from a multiple of 3 (1, 4 or 7) and every '2' with a number 2 away from a multiple of 3 (2, 5 or 8).

This means that, once we fix a patter, we have 3 choices for the first 3 slots, 2 choices for the next 3 slots, and the final slot will be fixed. So, we have

3\cdot 3\cdot 3\cdot 2 \cdot 2 \cdot 2 = 216

possible ways of following a fixed pattern. Since the number of patterns was 6, we have

216\cdot 6 = 1296

possible arrangements.

7 0
3 years ago
Read 2 more answers
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