Pls help ASAP ! <br><br><br> Pic is down below!

PLEASE HELP!! DUE SOON

mrs_skeptik [129]

Answer:

b=3a/8

a=8b/3

Step-by-step explanation:

b/a=k ( k is the constant proportional)

3/8=9/24=15/40

b/a=3/8

b=3a/8

a=8b/3

I hope this is right answer

7 0

3 years ago

MATTHEW HAS A BAG OF 100 PIECES OF CANDY. HE NEEDS TO SPLIT THE BAG BETWEEN HIS CLASSMATES IN HIS AM AND PM CLASS. HE HAS 20 STU

DiKsa [7]

Answer: They can recieve about 2.

Exact answer: 2.5

Step-by-step explanation:

If you divded 100 by 40, you get 2.5

Since there are 20 students in each AM and PM classes. you add 20 and 20, which is 40, then you divided by 100 which is 2.5

4 0

3 years ago

From a window 20 feet above the ground, the angle of elevation to the top of a building across

Nikitich [7]

Answer: The answer is 381.85 feet.

Step-by-step explanation: Given that a window is 20 feet above the ground. From there, the angle of elevation to the top of a building across the street is 78°, and the angle of depression to the base of the same building is 15°. We are to calculate the height of the building across the street.

This situation is framed very nicely in the attached figure, where

BG = 20 feet, ∠AWB = 78°, ∠WAB = WBG = 15° and AH = height of the bulding across the street = ?

From the right-angled triangle WGB, we have

$\dfrac{WG}{WB}=\tan 15^\circ\\\\\\\Rightarrow \dfrac{20}{b}=\tan 15^\circ\\\\\\\Rightarrow b=\dfrac{20}{\tan 15^\circ},$

and from the right-angled triangle WAB, we have'

$\dfrac{AB}{WB}=\tan 78^\circ\\\\\\\Rightarrow \dfrac{h}{b}=\tan 15^\circ\\\\\\\Rightarrow h=\tan 78^\circ\times\dfrac{20}{\tan 15^\circ}\\\\\\\Rightarrow h=361.85.$

Therefore, AH = AB + BH = h + GB = 361.85+20 = 381.85 feet.

Thus, the height of the building across the street is 381.85 feet.

8 0

3 years ago

WILL MARK BRAINLIEST!!!

hoa [83]

9514 1404 393

Answer:

a = 17
∠ABC = 78°

Step-by-step explanation:

The marked angles form a linear pair, so have a sum of 180°.

(4a +10) +(6a) = 180

10a = 170 . . . . . . . . . . subtract 10

a = 17 . . . . . . . . . . . . . divide by 10

__

Then the measure of angle ABC is ...

∠ABC = 4a +10 = 4(17) +10 = 68 +10 . . . . . substitute 17 for 'a'

∠ABC = 78°

5 0

2 years ago

A study of 25 graduates of 4-year public colleges revealed the mean amount owed by a student in student loans was $55,051. The s

Harman [31]

Answer:

Step 1

The data represent amount.

A 90% confidence interval for the population mean is,

First, compute t-critical value then find confidence interval.

The t critical value for the 90% confidence interval is,

The sample size is small and two-tailed test. Look in the column headed and the row headed in the t distribution table by using degree of freedom is,

The t critical value for the 90% confidence interval is 1.711.

A 90% confidence interval for the population mean is .

Step 2

It is reasonable to conclude that mean of the population is actually $55000 due to a 90% confidence intrerval for population mean is between $52461.23 and $57640.77 does include $55000.

The data represent amount.

A 90% confidence interval for the population mean is,

First, compute t-critical value then find confidence interval.

The t critical value for the 90% confidence interval is,

The sample size is small and two-tailed test. Look in the column headed and the row headed in the t distribution table by using degree of freedom is,

The t critical value for the 90% confidence interval is 1.711.

A 90% confidence interval for the population mean is .

It is reasonable to conclude that mean of the population is actually $55000 due to a 90% confidence intrerval for population mean is between $52461.23 and $57640.77 does include $55000.

5 0

2 years ago

Pls help ASAP ! Pic is down below!