Answer:
<1 and <2
<3 and <2
<1 and <4
Step-by-step explanation:
Adjacent angles are angles that are next to each other. In essence, they would share one aside in common. In this problem, the answers are the following,
<1 and <2
<3 and <2
<1 and <4
The area of the triangle extension is 12, because the total side length it is on is 18, and the segments to the sides of the triangle are 6 each, meaning 18-12=6, the height of the triangle. The base is given as 4, so 1/2(4x6)=24/2=12.
Add this to the area of the rectangle, 9x18=162, and 162+12=174.
The area is 174.
Answer: 3=24/8 24/8 - 1/8 = 23/8 or 2 7/8
Step-by-step explanation:
Exchange 3 into 24/8 which is still 3 but in 8th’s. Then subtract 1/8 from 24/8 which is 23/8 or 2 7/8
Answer:
a number that is divisible only by itself and 1 (e.g. 2, 3, 5, 7, 11).
Step-by-step explanation:
Answer:
V = (1/3)πr²h
Step-by-step explanation:
The volume of a cone is 1/3 the volume of a cylinder with the same radius and height.
Cylinder Volume = πr²h
Cone Volume = (1/3)πr²h
where r is the radius (of the base), and h is the height perpendicular to the circular base.
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<em>Comment on area and volume in general</em>
You will note the presence of the factor πr² in these formulas. This is the area of the circular base of the object. That is, the volume is the product of the area of the base and the height. In general terms, ...
V = Bh . . . . . for an object with congruent parallel "bases"
V = (1/3)Bh . . . . . for a pointed object with base area B.
This is the case for any cylinder or prism, even if the parallel bases are not aligned with each other. (That is, it works for oblique prisms, too.)
Note that the cone, a pointed version of a cylinder, has 1/3 the volume. This is true also of any pointed objects in which the horizontal dimensions are proportional to the vertical dimensions*. (That is, this formula (1/3Bh), works for any right- or oblique pyramid-like object.)
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* in this discussion, we have assumed the base is in a horizontal plane, and the height is measured vertically from that plane. Of course, any orientation is possible.
