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harina [27]
2 years ago
13

Help I don’t know the answer

Mathematics
1 answer:
labwork [276]2 years ago
7 0

Answer:

128.4 units.

Step-by-step explanation:

We need to set up ratios to do this problem.

Because both trapezoids are similar, we know that all corresponding sides are similar.

\frac{42}{35} = \frac{x}{107}

Simplify.

4,494 = 35x

Divide both sides by 35.

x = 128.4

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Things to watch out for:
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2 years ago
A basket holds at most 15 pounds of apples and oranges. There are no more than 6 pounds of apples in the basket. This graph show
Law Incorporation [45]
Im no genius or sure if its right, but I would definetly go with (12,4)
4 0
3 years ago
Read 2 more answers
A stadium can seat 46,000 people for a baseball game. One day, 49,442 people attended a game. How many people had to stand becau
suter [353]

Answer:

The answer is B.

Step-by-step explanation:

So, there are 46,000 seats for a baseball game and 49,442 attended. You need to subtract 46,000 from 49,442 to get the answer that is 3,442.

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3 years ago
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A jar consists of blue, red and green marbles. The probability of each of them is 2/7 , 3/k and 5/2k. Find the value of k.
jok3333 [9.3K]

Answer:

k = 77/10

Step-by-step explanation:

The jar consist of blue, red and green marbles . The probability of each of them can be described as follows.

probability of blue marbles = 2/7

probability of red marbles = 3/k

probability of green marbles = 5/2k

The sum of the individual probability is equals to 1. Therefore,

2/7 + 3/k + 5/2k = 1

collect like terms

(6 + 5)/2k = 1 - 2/7

11/2k =(7 - 2) /7

11/2k = 5/7

cross multiply

10k = 77

divide both sides by 10

k = 77/10

6 0
3 years ago
Simplify the expression. 8x^-10 y^'6 -2x^2y^-8 Write your answer without negative exponents.​
sergij07 [2.7K]

Answer:

8x^{-10}y^6 - 2x^2y^{-8} = \frac{8y^{14} - 2x^{12}}{x^{10}y^8}

Step-by-step explanation:

Given

8x^{-10}y^6 - 2x^2y^{-8}

Required

Simplify

Rewrite as:

8x^{-10}y^6 - 2x^2y^{-8} = \frac{8y^6}{x^{10}} - \frac{2x^2}{y^8}

Take LCM

8x^{-10}y^6 - 2x^2y^{-8} = \frac{8y^6*y^8 - 2x^2 * x^{10}}{x^{10}y^8}

Apply law of indices

8x^{-10}y^6 - 2x^2y^{-8} = \frac{8y^{14} - 2x^{12}}{x^{10}y^8}

8 0
2 years ago
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