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HACTEHA [7]
3 years ago
12

I need help for this question pllsssss

Mathematics
1 answer:
Korolek [52]3 years ago
5 0

Answer/Step-by-step explanation:

7. ✍️First Equation:

To generate the equation of the gray, which will be in the slope-intercept form, y = mx + b, we need to find the slope of the graph, m, and the y-intercept, b.

Using two points on the line, (2, 4) and (4, 0),

slope (m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{0 - 4}{4 - 2} = \frac{-4}{2} = -2

Substitute x = 2, y = 4 and m = -2 into y = mx + b, to find the value of b.

thus:

4 = (-2)(2) + b

4 = -4 + b

Add 4 to both sides

4 + 4 = b

b = 8

Substitute m = -2 and b = 8 into y = mx + b.

The first equation would be:

✅ y = -2x + 8

✍️Second Equation:

Using two points on the line, (1, 6) and (5, -2),

slope (m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{-2 - 6}{5 - 1} = \frac{-6}{4} = -\frac{3}{2}

Substitute x = 1, y = 6 and m = -³/2 into y = mx + b, to find the value of b.

thus:

6 = (-³/2)(1) + b

6 = -³/2 + b

Add ³/2 to both sides

6 + ³/2 = b

(12 + 3)/2 = b

15/2 = b

Substitute m = -³/2 and b = 15/2 into y = mx + b.

The second equation would be:

✅ y = -\frac{3}{2}x + \frac{15}{2}

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Step-by-step explanation:

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F_{t+1}=0.56\cdot 386+\left ( 1-0.56\right )385=385.56\approx 386

F_{t+2}=0.56\cdot 386+\left ( 1-0.56\right )385.56=385.806\approx 386

F_{t+3}=0.56\cdot 386+\left ( 1-0.56\right )385.806=385.914\approx 386

F_{t+4}=0.56\cdot 386+\left ( 1-0.56\right )385.914=385.962\approx 386

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