John's Bar 60 km away from Ben's Bar.
Doug's Bar is 40 km away from Kieran's Bar
John's Bar is 10 km nearer to Doug's Bar than Kieran's Bar
If I am to assume that these bar are in a liner position,
Ben's Bar Kieran's Bar John's Bar Doug's Bar
************* 60km*******************
*****************40 km ********************
*********30 km**************
Doug's Bar is 90 km away from Ben's Bar.
Ben to John = 60 km
John to Doug = 30 km
Ben to Doug = 60 + 30 = 90 km.
The answers are:
P(9, 2) = 72
P(5, 5) = 120
P(7, 7) = 5040
These are examples of permutations. The problems are asking us to find the total number of ways an event can happen.
In the first case, P(9, 2), we are asked to find the ways that 2 things can be chosen out of a group of 9.
9 x 8 = 72
P(5, 5) = 5 x 4 x 3 x 2 x 1
P(7, 7) = 7 x 6 x 5 x 4 x 3 x 2 x 1
It depends on what variable you are tying to solve for first. Say you are trying to solve for x first and then y on the first problem you wrote.
In substitution you solve one of the equations for example with
6x+2y=-10
2x+2y=-10
you solve 2x+2y=-10 for x
2x+2y=-10
-2y = -2y (what you do to one side of the = you do to the other)
2x=-10-2y (to get the variable by its self you divide the # and the variable)
/2=/2 (-10/2=-5 and -2y/2= -y or -1y, they are the same either way)
x=-5-y
now you put that in your original equation that you didn't solve for:
6(-5-y)+2y=-10 solve for that
-30-6y+2y=-10 combine like terms
-30-4y=-10 get the y alone and to do this you first get the -30 away from it
+30=+30
-4y=20 divide the -4 from each side
/-4=/-4 (20/-4=-5)
y=-5
now the equation you previously solved for x can be solved for y.
x=-5-y
x=-5-(-5) a minus parenthesis negative -(- gives you a positive
-5+5=0
x=0
and now we have solved the problem. x=0 and y=-5
Answer:
25% of 60 is 15
75% of 30 is 22.5
50% of 45.7 22.85
50% of 60 30
100% of 22.5 is 22.5
75% of 60 is 45
10% of 22.5 2.25
Step-by-step explanation:
Answer:
X represents The value of players on the field
Step-by-step explanation:
the numbers 0-11 are showing how many people would be on the field should an official game be played
