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Savatey [412]
3 years ago
13

Which problem would you use the following proportion to solve for? = what is 40% of 24? what percent is 24 of 40? twenty-four is

40% of what number? forty percent of 24 is what number?
Mathematics
2 answers:
ser-zykov [4K]3 years ago
5 0
First you have to remember that to find a percentage you can multiply a number by the percentage's decimal form, for example 40% of 100 would be .40 * 100.
Anyways, 24*.40 =9.6.
To find the percentage however, you must divide 24/40 which equals 0.6, which is equal to the percentage 60%.
To find the third question, you must multiply 24 by 2.5 (0.4 * 2.5 = 1) and you should get 60.
The last question you may have made a typo on, you repeated the first question.
anastassius [24]3 years ago
3 0

Answer: A

Step-by-step explanation:

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this is pretty easy to most people its just that ive never studied this (open attachment) im in year 7
yKpoI14uk [10]

Answer:

a. 8/20 - 2/5

b. 2/8

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
A bank loans ​$2100 to a business at 7​% for 3 months. How much simple interest will the bank​ earn?
Natali [406]

Answer:

  $36.75

Step-by-step explanation:

The amount of interest payable is given by ...

  I = Prt = $2100·0.07·(3/12) . . . . . . . . t is in years

  I = $36.75

The bank earned $36.75 on the loan.

7 0
3 years ago
Let X, the number of flaws on the surface of a randomly selected boiler of a certain type, have a Poisson distribution with para
kvasek [131]

Answer:

(a) 0.932

(b) 0.0653

(c) 0.032

(d) 0.316

(e) 0.251

Step-by-step explanation:

From the table with mean parameter μ = 5, we can compute the following cumulative and density probability

(a) P(X \leq 8) = 0.932 (cumulative)

(b) P(X = 8) = 0.0653 (density)

(c) P(9 \leq X) = 1 - P(X \leq 9) = 1 - 0.968 = 0.032 (cumulative)

(d) P(5 \leq X \leq 8) = P(X \leq 8) - P(X \leq 5) = 0.932 - 0.616 = 0.316 (cumulative)

(e) P(5 < X < 8) = P(X \leq 8) - P(X \leq 5) - P(X = 8) = 0.932 - 0.616 - 0.0653 = 0.251

5 0
3 years ago
A certain paper suggested that a normal distribution with mean 3,500 grams and a standard deviation of 560 grams is a reasonable
Natalka [10]

Answer: the probability that a randomly selected Canadian baby is a large baby is 0.19

Step-by-step explanation:

Since the birth weights of babies born in Canada is assumed to be normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = birth weights of babies

µ = mean weight

σ = standard deviation

From the information given,

µ = 3500 grams

σ = 560 grams

We want to find the probability or that a randomly selected Canadian baby is a large baby(weighs more than 4000 grams). It is expressed as

P(x > 4000) = 1 - P(x ≤ 4000)

For x = 4000,

z = (4000 - 3500)/560 = 0.89

Looking at the normal distribution table, the probability corresponding to the z score is 0.81

P(x > 4000) = 1 - 0.81 = 0.19

5 0
3 years ago
The Big Wheel at a theme park has a diameter of 5m. How far would you travel in one complete revolution of the wheel?
vampirchik [111]

Answer:

15.71m

Step-by-step explanation:

One revolution is equal to the circumference of the wheel

Circumference = πD

22/7 X 5 = 15.71m

6 0
3 years ago
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