Answer:
a. 8/20 - 2/5
b. 2/8
Step-by-step explanation:
Answer:
$36.75
Step-by-step explanation:
The amount of interest payable is given by ...
I = Prt = $2100·0.07·(3/12) . . . . . . . . t is in years
I = $36.75
The bank earned $36.75 on the loan.
Answer:
(a) 0.932
(b) 0.0653
(c) 0.032
(d) 0.316
(e) 0.251
Step-by-step explanation:
From the table with mean parameter μ = 5, we can compute the following cumulative and density probability
(a)
(cumulative)
(b) P(X = 8) = 0.0653 (density)
(c)
(cumulative)
(d)
(cumulative)
(e) 
Answer: the probability that a randomly selected Canadian baby is a large baby is 0.19
Step-by-step explanation:
Since the birth weights of babies born in Canada is assumed to be normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = birth weights of babies
µ = mean weight
σ = standard deviation
From the information given,
µ = 3500 grams
σ = 560 grams
We want to find the probability or that a randomly selected Canadian baby is a large baby(weighs more than 4000 grams). It is expressed as
P(x > 4000) = 1 - P(x ≤ 4000)
For x = 4000,
z = (4000 - 3500)/560 = 0.89
Looking at the normal distribution table, the probability corresponding to the z score is 0.81
P(x > 4000) = 1 - 0.81 = 0.19
Answer:
15.71m
Step-by-step explanation:
One revolution is equal to the circumference of the wheel
Circumference = πD
22/7 X 5 = 15.71m