Answer: 29.28 years
Explanation:
From Kepler's third law the square of orbital period of revolving celestial body is proportional to the cube of semi -major axis from the body it is revolving about.
P² =A³
Where, P is the orbital period in years and A is the semi-major axis in AU (Astronomical units)
It is given that, For Saturn, A = 9.5 AU. We need to find P
⇒P² = (9.5 AU)³
⇒P² = 857.38
⇒P = 29.28 years
Thus, the orbital period of Jupiter is 29.28 years around the Sun.
Answer:
There is one solution and that answer is mixed number form 1 5/7 or exact form 12/7
Step-by-step explanation:
Answer:
C.Infinitely many solutions
I solved by substitution
Infinitely many solutions
Answer:
14,168
Step-by-step explanation:
15400
Find 1% and times it by 8
Take away 8% from 15400
15400-1232=14168
